Azzera filtri
Azzera filtri

How to calculate the points of a line which lies inside polygons?

2 visualizzazioni (ultimi 30 giorni)
Hi all,
I have GPS coordinates of an off-road vehicle and I have to check when the vehicle lies on a road or on a field. I have downloaded the shape file of my region, where there are the bounding box of each field. Below, you will find my code, that is very slow because in the shape file there are around 3e5 polygons. How could I speed up the code? In my opinion, the calculation could be speeded up, if I can avoud the inner for, but I do not know how can I do it.
for i=1:length(GPSData)
for iS=1:length(FieldUseSHP)
if any(a)==1
Thank you in advance
Best regards,
  4 Commenti
Adam Danz
Adam Danz il 3 Apr 2019
I see. What does the data look like that produces the image you shared? In other words, the brown field contains ~20 line segments and the yellow field contains 4 segments. Do you have the 20 (x,y) coordinates that produce the brown field and the 4 (x,y) coordinates that produce the yellow field?
If yes, are those coordinates used to define the polygon used in inpolygon()?
Also, what are your two loops? You should have a set of (x,y) coordinates that define the tractor's trajectory and those whould be the first inuts to the inpolygon() function.
pietro il 4 Apr 2019
I have several GPS vehicle data, each is an acquisition and the first for loops through all the acquisitions. The other for loops through all the polygons of field plot contours.
In the plot I have shown only two field countours, that are the closest to the chosen acquisition.

Accedi per commentare.

Risposte (1)

Matt J
Matt J il 3 Apr 2019
fconv=@(z) z(:).';
Longitude=cell2mat( cellfun( fconv, {GPSData.Longitude},'uni',0) )*pi/180;
Latitude=cell2mat( cellfun( fconv, {GPSData.Latitude},'uni',0) )*pi/180;
for iS=1:length(FieldUseSHP)
a=inpolygon(Longitude, Latitude,FieldUseSHP(iS).Lon,FieldUseSHP(iS).Lat);

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by