error using contains function

when I use contains function in a loop it show me that error message, even though Raw is a cell array, and also the compilation complete and the code after if contains(Raw(i,2),serie)==1 works well.
is there a solution for that ?

5 Commenti

Matt J
Matt J il 22 Apr 2019
Modificato: Matt J il 22 Apr 2019
I suggest you provide code and input data that let's us reproduce the problem.
RMS=cellstr(RMS);
BaseDir = 'C:\Temp'; % Set as you need
[FileName, FilePath] = uigetfile('*.xlsx', ...
'Please choose an Excel file', BaseDir);
File = fullfile(FilePath, FileName);
prompt='Quelle fenêtre ?';
numbofsheet=input(prompt);
[Num, Txt, Raw] = xlsread(File,numbofsheet);
sizeRaw=size(Raw);
for i=2 : sizeRaw(1,1)
if contains(Raw(i,2),serie)==1
for j=2 : rowRMS(1,1)
if contains(Raw(i,1),RMS(j,1))==1
if contains(Raw(i+1,8),MeasTypeID)==1
Raw(i+1,9)=RMS(j,2);
else
if contains(Raw(i+2,8),MeasTypeID)==1
Raw(i+2,9)=RMS(j,2);
else
if contains(Raw(i+3,8),MeasTypeID)==1
Raw(i+3,9)=RMS(j,2);
end
end
end
end
end
end
end
xlswrite(File,Raw,numbofsheet);
Matt J
Matt J il 22 Apr 2019
Modificato: Matt J il 22 Apr 2019
You need to provide the variables (in a .mat file) that would let us run the important section of the code as follows:
load yourMATFile.mat
sizeRaw=size(Raw);
for i=2 : sizeRaw(1,1)
if contains(Raw(i,2),serie)==1
for j=2 : rowRMS(1,1)
if contains(Raw(i,1),RMS(j,1))==1
if contains(Raw(i+1,8),MeasTypeID)==1
Raw(i+1,9)=RMS(j,2);
else
if contains(Raw(i+2,8),MeasTypeID)==1
Raw(i+2,9)=RMS(j,2);
else
if contains(Raw(i+3,8),MeasTypeID)==1
Raw(i+3,9)=RMS(j,2);
end
end
end
end
end
end
end

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 Risposta accettata

Adam Danz
Adam Danz il 22 Apr 2019
Modificato: Adam Danz il 22 Apr 2019

0 voti

I can see in your screen shot of workspace variables that your "Raw" array contains mostly NaN values.
According to your error message, the first argument of contains() must be a string array, char vector, or cell array of char vectors. "Raw" appears to be a cell array with lots of NaNs.
You probably want to just skip iterations where the input to contains() includes NaN values (or you might want to use a different method).

5 Commenti

maybe I understand now
contains works for Raw(2,2); but doesn't work when it find NaN
Yep! One way to avoid iterations with NaNs is something like this:
if all(~isnan(Raw(i,1))) & contains(Raw(i,1),RMS(j,1))==1
Adam Danz
Adam Danz il 22 Apr 2019
Modificato: Adam Danz il 22 Apr 2019
You need to do some exploring. Some trial and error. The error message tells you that the input to isnan() does not accept cell arrays. So try this
isnan(out{2,2})
% or
isnan([out{2,2}])
More more information on how to work with cell arrays:
thank you

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