How can I solve this ODE 1000 times with random variables?

3 visualizzazioni (ultimi 30 giorni)
So I have this code:
tspan=[1 7];A0=rand;P0=rand;g=rand;p=rand;B=rand;
[t,x] = ode45(@(t,x) [-g*x(1) + p*x(1); -x(1)*x(2)+ B*x(2)], tspan, [A0 P0])
And it works perfectly.
But what I want to do is run it 1000 times and change the random inputs each time, and generate new solutions every time. I've tried using the following:
n = 1000;
result = zeros(n,1);
for k=1:n
tspan=[1 7];A0=rand;P0=rand;g=rand;p=rand;B=rand;
[t,x(n)] = ode45(@(t,x) [-g*x(n(1)) + p*x(n(1)); -x(n(1))*x(n(2))+ B*x(n(2))], tspan, [A0 P0])
result(k) = x(n);
end
But I get the error
Index exceeds the number of array elements (2).
Error in @(t,x)[-g*x(n(1))+p*x(n(1));-x(n(1))*x(n(2))+B*x(n(2))]
Error in odearguments (line 90)
f0 = feval(ode,t0,y0,args{:}); % ODE15I sets args{1} to yp0.
Error in ode45 (line 115)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Any advice?
  1 Commento
Thomas Veith
Thomas Veith il 30 Mag 2019
Alternatively, if I try this:
n = 1000;
result = zeros(n,1);
for k=1:n
tspan=[1 7];A0=rand(n);P0=rand(n);g=rand(n);p=rand(n);B=rand(n);
[t,x] = ode45(@(t,x) [-g*x(1) + p*x(1); -x(1)*x(2)+ B*x(2)], tspan, [A0 P0])
result(k) = x(n);
end
I get the following error:
Error using odearguments (line 93)
@(T,X)[-G*X(1)+P*X(1);-X(1)*X(2)+B*X(2)] must return a column vector.
Error in ode45 (line 115)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);

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Risposta accettata

Star Strider
Star Strider il 30 Mag 2019
You coded your differential equation correctly. Your ‘x’ variable has only two elements, so you cannot use ‘n’ (or ‘k’) to subscript them.
See if this does what you want:
n = 1000;
result = cell(n,1);
for k=1:n
tspan=[1 7];A0=rand;P0=rand;g=rand;p=rand;B=rand;
[t,x] = ode45(@(t,x) [-g*x(1) + p*x(1); -x(1)*x(2)+ B*x(2)], tspan, [A0 P0]);
result{k} = x;
end
Note that because the time vector can change between your ode45 calls, a cell array is most appropriate. If you want a specific number of values to be returned each iteration, define ‘tspan’ as a vector of more than two elements.
  2 Commenti
Star Strider
Star Strider il 30 Mag 2019
As always, my pleasure!
You might also want to store your parameters, so you know what the solution used.

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