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second largest peak value

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Ramesh Bala
Ramesh Bala il 12 Giu 2019
Commentato: Ramesh Bala il 6 Ago 2019
I'm getting the amp of second largest peak as correct but the time is wrong ?
How to obtain the second highest value X,Y from this and plot as already Y is correct ,X seems to be in wrong region?
s=load ('30827.mat');
load t.mat;
[PkAmp, PkTime] = findpeaks(abs(hilbert(signal(1,:))),t);
[highestPeak, indexOfHighestPeak] = max(PkAmp);
[a2(1),b6]=max(PkAmp(PkAmp<max(PkAmp))); % to get second largest peak value
% error is the time value calcluate and plotted wrong??
Highesttime(1,:) = t(b2);
Highest2time(1,:) = t(b6);
hold on
plot(PkTime, PkAmp, '^r', 'MarkerFaceColor','r')
xlim([0 0.0006]);ylim([-inf inf])
grid on
hold on,plot(t(b6),a2(1),'ko')
hold off

Risposta accettata

Alex Mcaulley
Alex Mcaulley il 12 Giu 2019
To obtain the coordinates of the second peak you just need:
[PkAmp, PkTime] = findpeaks(abs(hilbert(signal(1,:))),t);
[~,idx] = sort(PkAmp,'descend');
PkAmp(idx(2)) %Amplitude of the second peak
PkTime(idx(2)) %Time of the second peak
  13 Commenti
Ramesh Bala
Ramesh Bala il 6 Ago 2019
Dear Alex
I have one more silly doubt in removing the index,I'm trying to find now the the largest time instead of Amp.So,I have used 'ascend' function which helps me to plot the the required time.
clear all
close all
format long;
S(:,1) = [25 25 21.4 17.92 28.5 32.07 30 35 20 15];
S(:,2)= [10 15 8.5 12.07 8.5 12.07 5 5 5 5 ];
for i=1:numel(filenames)
s(i)=load (filenames{i});
signal(i,1:length(s(i).ans))=s(i).ans; % loading the signals from the scanning pts
load t.mat; %loading the time values
for k=1:1:length(S)
[a(k),b2]=max(abs(hilbert(signal(k,:)))); % first peak amp & index
%finding the peaks
[PkAmp, PkTime] = findpeaks(abs(hilbert(signal(k,:))),t);
[~,idx] = sort (PkTime, 'ascend' );
b6(k) = idx(4); % Index of the fourth largest peak
a6(k) = PkAmp(b6(k)); % Amplitude of the fourth largest peak
time4(k)= PkTime (b6(k)); % Time of the fourth largest peak
hold on;grid on
plot(PkTime, PkAmp, '^r', 'MarkerFaceColor','r')
%plotting 4th largest
hold on,plot(time4(k), a6(k),'ko')
hold off
As per the script it plots the 4th largest PKTime peak .But how to remove other PkTime based on highest "a" highest PKAmp and then recontinue to plot the graph by taking highest(PKAMP) as PKTIME 1?
Ramesh Bala
Ramesh Bala il 6 Ago 2019
sa ve.PNG

Accedi per commentare.

Più risposte (1)

Steven Lord
Steven Lord il 13 Giu 2019
Use the islocalmax function with the 'MaxNumExtrema' option.


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