How can I put the value of z in a matrix and later call it as z(1,i) and z(2,i) in the while loop?

close all;
dt = 0.1;%time step
u1=1;
u2=1;
c = u2-u1;
u = sign(u2-u1);
z = u*c;


k=0.12;
m=2.21;%initial parameters

v=1;
a=1.4;

tend=1000;

t=0;
i=1

while t < tend-2*dt
    vh=v(i)-dt*k*z(i)/ (2*m);
    z(i+1) = z(i)+ dt*vh;
    %a(i+1)= -k*z(i)/2;
    v(i+1)= vh-dt*k*z(i+1)/ (2*m);% + dt*a(i+1)/2;
    i = i+1;
    t = t + dt
end
plot(z);

[Walter Roberson]

What should be in z(1,i) and what should be in z(2,i)?

[Advait Sinha]

Z(2,i)= z(1,i)+dt*vh

Basically z(1,i) and z(2,i) would give the position of the first two coordinates of the linear system represented by the code. Z can be any matrix such that z(:,1) = [0;1]

Answer 1

[sourav malla]

If you want a matrix of 2 column with changing row values then you can do like this:-

while i<t
    Z(2,i)= z(1,i)+dt*vh;
    i=i+1
end

Answer 2

[Advait Sinha]

But then what would happen to the other equations that also make use of z. Also would I need to implement z as a matrix before the while loop too