Insert desired number of spaces in the string contains numerical value

Hi,

I need to print the below string which is in loop as

0 STR 1

where the first character is zero then 30 spaces then string STR and numerical 1 after five spaces

for this i wrote the statement as

txt = sprintf('0%30sSTR%5s%d',1);

But answer is not expected as above it gave the result as below

txt =

    '0                             STR'

[Guillaume]

It's not entirely clear what you want and your example is lacking since your format string has three format specifiers (two strings and a decimal), yet you only give it one number.

• Is STR an input (i.e. it can be some other string) or a fixed part of the format?
• If it's actually an input does the 30 space change depending on the length of the input or is it fixed regardless?
• Similarly, is the 5 spacing dependent on the number of digits in the number (i.e. 2 digits = spacing of 4, 3 digits = spacing of 3, etc.)?

[Bhaskar R]

Guillaume, only decimal part changes

• STR is not an input it is a fixed part
• 30 spaces also a fixed part
• 5 spaces also fixed

Only last one is decimal value it may varies as single or multiple digits

Note: first character zero is fixed

-Thanks

Answer 1

[Guillaume]

The clearest way to achieve what you want is to put the spaces explicitly in your format string:

txt = sprintf('0                              STR     %d', istep)

or construct it explicitly:

txt = sprintf(['0', blanks(30), 'STR', blanks(5), '%d'], istep)

You could also use the format string that you've specified, by giving it spaces for the string formats:

txt =  sprintf('0%30sSTR%5s%d', ' ',  ' ', istep);

But in my opinion, it's less clear as to the intent than the other two options.

[Bhaskar R]

Yeah, its worked(3rd one required)

Thanks :-)

Answer 2

[Matt J]

How about

txt="0                                         STR     "+1

[Matt J]

Or, similarly,

txt="0"+blanks(30)+"STR"+blanks(5)+1