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How can i find cumulative mean inside a for loop?

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Hey everyone,
I have a code which helps me to calculate the mean values. Each of the "cellList.meshData(j)" corresponds to a single column vector of values. I would like it to give me the total mean of all 25 cells. The following code gives me the mean for each cell.
for j=1:25
data=cellList.meshData(j);
if isempty(data{1,1})
continue
end
mean_int_val = mean(cellList.meshData{j}{1,1}.signal2);
end
  1 Commento
Johannes Fischer
Johannes Fischer il 3 Set 2019
To imporve code-readability, I would not use 'continue' in this case:
for j = 1:25
data = cellList.meshData(j);
if ~isempty(data{1, 1})
mean_int_val = mean(cellList.meshData{j}{1, 1}.signal2);
end
end

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Risposta accettata

Nicolas B.
Nicolas B. il 3 Set 2019
Modificato: Nicolas B. il 3 Set 2019
Hi,
For your situation, you should consider that . So they are 2 situations:
  1. All vectors have the same size
  2. Vectors can have different sizes
If you are in the first situation, I would simply keep all mean_int_val and simply recompute the the mean of all means.
nData = 25;
mean_int_val = NaN(1, nData);
for j=1:nData
data=cellList.meshData(j);
if isempty(data{1,1})
continue
end
mean_int_val(j) = mean(cellList.meshData{j}{1,1}.signal2);
end
mean_total = mean(mean_int_val, 'omitnan');
If you are in the second situation, I would also keem the number of samples and then compute the mean.
nData = 25;
mean_int_val = NaN(1, nData);
mean_size = NaN(1, nData);
for j=1:nData
data=cellList.meshData(j);
if isempty(data{1,1})
continue
end
mean_int_val(j) = mean(cellList.meshData{j}{1,1}.signal2);
mean_size(j) = numel(cellList.meshData{j}{1,1}.signal2);
end
mean_total = sum(mean_int_val .* mean_size) / sum(mean_size);
  4 Commenti
Nicolas B.
Nicolas B. il 3 Set 2019
Thanks for the comment. I corrected it with j instead of i (bad habits).
In my suggestions, the mean of all means is saved in mean_total variable.
Meghana Balasubramanian
Meghana Balasubramanian il 3 Set 2019
Yes, I just tried the first solution out. It works for my purposes.
Thank you! :)

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