How can I Write a code that will allow a vector of positive integers in x, as a user input, to evaluate the equation listed below.For odd numbers we will use the following equation
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
x= input('\nPlease input a 5 values in vector notation:');
i = 1;
for i = 1:5
if rem(i,2) ==1; i = 2.*(i.^2) + 8*i - 3;
if rem(i,2)==0;
i = 2.*(i.^2) - 8*i + 3;
end
end
i=i+1
end
disp(i)
3 Commenti
Risposta accettata
dpb
il 18 Set 2019
x= input('\nPlease input a 5 values in vector notation:');
b=nan(size(x)); % initialize to something
isodd=mod(x,2)==1;
y(isodd) =polyval([2 8 -3],x(isodd); % evaluate 2x.^2 + 8x - 3 for odd x
y(~isodd)=polyval([2 -8 3],x(~isodd); % evaluate 2x.^2 - 8x + 3 for even x
disp(y)
3 Commenti
dpb
il 18 Set 2019
Sure... :)
Just carry on as you began with rough93 pattern incorporating my comments...since it is homework, let's see your continuing work towards a solution rather than just "giving away the store"....will continue to provide hints or answer specific questions other than "just do it"... :)
Più risposte (1)
rough93
il 18 Set 2019
It looks like you're using i within your calculations when you should be using x. Assuming your vecor input is [1 2 3 4 5]:
i = 1;
for i = 1:5
if rem(x(1),2) ==1; x = 2.*(x.^2) + 8*x - 3;
if rem(x,2)==0;
x = 2.*(x.^2) - 8*x + 3;
end
end
i=i+1
end
You may also want to make your second if an ifelse and add an else condition to clean up the code and prevent errors.
1 Commento
dpb
il 18 Set 2019
Modificato: dpb
il 18 Set 2019
The if above for rem(x,2)==0 won't work as it returns a logical vector which will be true only if all elements are true. Need to test x(i) in the loop.
The assignment is also global and overwrites the input x vector in the calculations.
Also incrementing i is automagic in the loop for expression and neither the initialization before the loop nor the incrementing statement are of any use and should be eliminated entirely.
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!