I cannot seem to get a second line for the forward finite difference

1 visualizzazione (ultimi 30 giorni)
clc
clear
close all
h = [-2 -1.75 -1.5 -1.25 -1 -.75 -.5 -.25 0 .25 .5 .75 1 1.25 1.5 1.75 2];
x = [-2 -1.75 -1.5 -1.25 -1 -.75 -.5 -.25 0 .25 .5 .75 1 1.25 1.5 1.75 2];
y = @(x) x.^3 - 2*x + 4; %start function
yd = @(x) 3*x.^2 - 2; %first deriv
ydd = @(x) 6*x; %second deriv
for i = 1:2
for j = 1:17
xi = x(i);
hj = h(j);
d1 = yd(xi);
d2 = ydd(xi);
%forward diff
f1 = (y(xi+hj) - y(xi))/hj;
f2 = (y(xi+2*hj) - 2*y(xi+hj))/(hj.^2);
%backward diff
b1 = (y(xi) - y(xi-hj))/hj;
b2 = (y(xi)-2*y(xi-hj)+y(xi-2*hj))./(h.^2);
%centered diff
c1 = (y(xi+hj) - y(xi-hj))/(2*hj);
c2 = (y(xi+hj) - 2*y(xi)+y(xi-hj))/(hj.^2);
plot(x,yd(x));
hold on
plot(x,d2,'r');
hold off
legend('Analytic','Forward','Backward','Center')
end
end
This is the code I've gotten so far. For the second plot I have tried everything I can think of and it will not plot. Why is this?
  1 Commento
Walter Roberson
Walter Roberson il 25 Set 2019
You should not be plotting inside your for j loop. You should be recording the results into a vector and plotting after the loop.
plot(x,yd(x));
You current point is xi so yd(xi) what you should be concerned with recording for later.

Accedi per commentare.

Risposte (1)

Image Analyst
Image Analyst il 25 Set 2019
Looks like d2 is a scalar, not a vector (a list of values for each x value).

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