Azzera filtri
Azzera filtri

creating a loop and functions

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Tarek Zaqout
Tarek Zaqout il 10 Ott 2019
Commentato: Peter Perkins il 15 Ott 2019
Hi,
I'm trying to perform a simple model but can't seem to create a loop. The issue is that I use known values (ho and hl) to solve the equation.
Then I need to use a data set of (ho) consisting of a column of 298 into the equation while the (hl) is from the previous iteration.
here is my code, I'm using a (for loop), but the problem is that it produces the same value of the intitial (hl) for all 298 outputs. Any ideas what is wrong?
Al=36000;
Qr=31.5;
Ai=3.14*(150/2)^1/2;
Time=table2array(wl(:,1));
wl_sea=table2array(wl(:,3));
wl_lagoon=table2array(wl(:,4));
ho=20.62949/100;
deltat=0;
hl=23.908655/100;
kf=0.3;
% the first step is to use the first known lagoon water level to calculate
% the next level using the sea water level as input
hl0=hl+(deltat*(Ai/Al))*((2*9.81)^0.5/kf)*((ho-hl)/(abs(ho-hl)^0.5)+(deltat*(Qr/Al)))
ho=wl_sea;
for i=1:1:298
hi = hl0;
h(i)=hi;
hi = hi+(deltat*(Ai/Al))*((2*9.81)^0.5/kf)*((ho-hi)/(abs(ho-hi)^0.5)+(deltat*(Qr/Al)))
end
  6 Commenti
Tarek Zaqout
Tarek Zaqout il 10 Ott 2019
alright to make it simpler.
hi=0.2391;
then assuming all variables are defined.
for i=1:298
hi = hi+(deltat*(Ai/Al))*((2*9.81)^0.5/kf)*((ho-hi)/(abs(ho-hi)^0.5)+(deltat*(Qr/Al)))
end
Peter Perkins
Peter Perkins il 15 Ott 2019
Loop issues aside, you definitely can make this (and the other two lines like it)
Time = table2array(wl(:,1))
simpler:
Time = wl.Time % or whatever the var name is

Accedi per commentare.

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