using convolution with matlab

x[n]=n^3-n^2, 0<n<3
h[n]=1/n, -2<n<-1
y[n] is the convolution of x[n] and h[n]
how can i compute y[n] ?

 Risposta accettata

Wayne King
Wayne King il 21 Set 2012
With all due respect, I think you need to take some time to read the MATLAB documentation.
n = 0:3;
x=n.^3-n.^2;
m=[-2:-1];
h=1./m;
y = conv(x,h)

3 Commenti

i did try, but i am not a good learner somehow...
anyway, thanks for ur kind replies. it really helps a lot!
Wayne King
Wayne King il 21 Set 2012
You should accept people's answers if they help you.
ok, just done!

Accedi per commentare.

Più risposte (1)

Wayne King
Wayne King il 21 Set 2012

0 voti

Use the function conv()
See the help for conv()

1 Commento

ive tried, but it does not work at all.
n=[0:3];
x=n^3-n^2
m=[-2:-1];
h=1/m
y= conv(x,h)
no results at all, could u help?

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by