find max value in a Matrix using loops only

hallo,

I can find only two max with this code. can you help me please to find all Max (more than 1 or 2) with the corrent code in this Matrix X=[1,2,3;7,1,9;4,9,6;9,8,7].

X=[1,2,3;7,1,9;4,9,6;9,8,7];
Max = -Inf;
row = 0;
column = 0;
row1 = 0;
column1 = 0;
for i = 1:size(X, 1)
  for j = 1:size(X, 2)
    if X(i, j) > Max
      Max = X(i, j);
      row = i;
      column = j;
    end
    if X(i, j) >= Max
      Max = X(i, j);
      row1 = i;
      column1 = j;
    end
  end
end
X
Max
row
column
row1
column1

[dpb]

Find global maximum first, then find the matching locations. Save the location indices in arrays instead of named variables. Mimic the output of the builtin max function.

Answer 1

[JESUS DAVID ARIZA ROYETH]

solution:

X=[1,2,3;7,1,9;4,9,6;9,8,7];
Max = -Inf;
 row = [];
 column = [];
 for i=1:size(X,1)
     for j=1:size(X,2)
         if X(i,j)>=Max
             Max=X(i,j);
         end         
     end
 end
  for i=1:size(X,1)
     for j=1:size(X,2)
         if X(i,j)==Max
             row(end+1)=i;
             column(end+1)=j;
         end         
     end
  end
X
Max
row
column

[Zed Ferch]

Hallo Jesus David,

thank you very much for your help, the code word very well, thats nice :)