Decision Branching Error in matlab onramp
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How to crack this error? The input data and solution provided by the matlab sources are same still the error is occuring.
6 Commenti
Risposta accettata
Steven Lord
il 2 Dic 2019
That might be checking that the densities that are printed as text when doPlot is 0 exactly match the densities that would be printed by "the code as shown above". The code you're using doesn't exactly match: note that your code doesn't display a space between "of" and the name of the element. Try adding the spacing before and after the element name (as I believe "the code as shown above" does) and see if that allows you to pass the test case.
4 Commenti
Steven Lord
il 17 Dic 2019
Compare:
x = 1;
y = 2;
disp("The value of x is" + x + "and the value of y is" + y)
disp("The value of x is " + x + " and the value of y is " + y)
The two phrases displayed are not identical. If your code displayed the first of those phrases but the exercise expected the second your code would not pass the test.
Damilola Adeniji
il 18 Dic 2019
Hi Steve
Thanks for the quick response.
Even after following the phrase is still saying incorrect.
thanks.
Più risposte (7)
Ivan Derkunskii
il 8 Mar 2020
You'll be laughing, but you need just put spaces inside the phrases "The density of the" and "is" so that they look like "The density of the " (a space after the whole phrase) and " is " (spaces before and after the word).
8 Commenti
Rahul Das A H
il 5 Feb 2022
load datafile
density = data(:,1);
if doPlot == 1
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
end
Walter Roberson
il 5 Feb 2022
Comparing to 1 is not necessary in the case where the values are guaranteed to be either 0 or 1.
In the case where the values are not guaranteed to be one of those two, then you need to know whether the rule is that the number must be exactly 1 to pass, or if the rule is that the number must not be zero to pass.
Bongani Tavengwa
il 4 Giu 2020
if doPlot
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp("The density of" + element + "is" + density)
end
3 Commenti
Steven Lord
il 4 Giu 2020
name = "Bongani Tavengwa";
disp("Do you see the problem now" + name)
disp("Do you see the problem now " + name)
Do you see the difference in the two displayed statements? What's the difference between the second and third lines of code and what impact does that difference have in the displayed text?
Sreekanth K M
il 17 Giu 2020
if doPlot
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp(" The density of " + element + " is " + density)
end
6 Commenti
Surya Karthik Nadupalle
il 22 Ago 2020
Modificato: Surya Karthik Nadupalle
il 22 Ago 2020
The problem is solved only when you give gaps between words in the bracket. Notice the spacing i gave. It worked
disp(" The density of " + element + " is " + density)
3 Commenti
Walter Roberson
il 25 Giu 2021
We do not know what code you are using.
I also have not seen a copy of the question being asked.
梦波
il 22 Ago 2023
It's not a logical error, but a format error. You need add spaces in the double quotes
0 Commenti
Al
il 8 Feb 2024
If you find error, follow these instructions
- First of all, refresh the editor (or close all tab and resume the course)
- Then copy the following code
if doPlot == 1
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp("The density of"+element+"is"+density)
end
3. Now submit the task
0 Commenti
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