About logical calculation. Is this a bug?

3.jpg
what happened to this case? Is this a matlab bug?

1 Commento

logical should be 1 at the lower left corner of the picture.
-1<p_grad == 1, p_grad < 1 ==1, bug -1<p_grad<1 == 0

Accedi per commentare.

 Risposta accettata

Adam Danz
Adam Danz il 14 Gen 2020
Modificato: Adam Danz il 14 Gen 2020
The operation
p_grad = 1.1200e-17;
-1 < p_grad < 1
works from left-to-right. It is interpretted as
p_grad = 1.1200e-17;
(-1 < p_grad) < 1
which is simplified to
1 < 1
which equals 0 (false).
To determine if p_grad is between -1 and 1, (parentheses optional)
(-1 < p_grad) && (p_grad < 1) % for scalar values
(-1 < p_grad) & (p_grad < 1) % for non-scalar values or when
% number of element is unknown

3 Commenti

Oh. I see. Thank you.
If I remember correctly, as of release R2019b if you try to use that idiom in a file in the Editor Code Analyzer will warn you that it doesn't do what you think it does.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Centro assistenza e File Exchange

Prodotti

Release

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by