How to compare each element of a matrix with a number ?

Hello everyone!

I have this problem:

I have this matrix (10x1 double): A = [10; 20; 30; 40; 50; 60; 70; 80; 90; 100]

I would like to compare each element in this matrix with numbers. Precisely like this:

If the elements of A <= 50 then it is false, if the elements of A> 50 then it is true. So get this as a final result: B=[10 false; 20 false; 30 false; ......; 100 true]

How could I do ?

I use this code (but it dosen't work):

B=[ ]

if all(A <= 50)

B = ('False');

else

if all(A > 50)

B = ('True');

end

end

Thanks for the answers!

Answer 1

[Adam Danz]

Since A are of class double and the </> comparisons will produce logical values, you cannot combine them in a matrix.

Instead, here are 3 options.

Option 1: Matrix (converting logical values to double)

A = [10; 20; 30; 40; 50; 60; 70; 80; 90; 100]; 
B = [A, A > 50]; 

% Result
% B =
%     10     0 
%     20     0
%     30     0
%     40     0
%     50     0
%     60     1
%     70     1
%     80     1
%     90     1
%    100     1

Option 2: Table

A = [10; 20; 30; 40; 50; 60; 70; 80; 90; 100]; 
T = table(A, A > 50, 'VariableNames',{'A','TF'}); 

% Result
% T =
%      A      TF  
%     ___    _____
% 
%      10    false
%      20    false
%      30    false
%      40    false
%      50    false
%      60    true 
%      70    true 
%      80    true 
%      90    true 
%     100    true 

Option 3: Cell array

A = [10; 20; 30; 40; 50; 60; 70; 80; 90; 100]; 
B = {A, A > 50}; 

% Result
% B =
%     {10×1 double}    {10×1 logical}

[Riccardo Busin]

Thanks for your help!

[Adam Danz]

Glad I could help!

Answer 2

[Naveen Miriyala]

A=[2 3 4 5];

T=6;

A=[A,A<6]