Getting the max value of a certain column, fetching the entire row from a 3D matrix and write those in a new matrix

2 visualizzazioni (ultimi 30 giorni)
Arup Bhattacharya
Arup Bhattacharya il 19 Gen 2020
Commentato: Arup Bhattacharya il 20 Gen 2020
Hi,
I have a 3D matrix Once_Still_3D of form 68 x 8 x 30, with 30 being the timesteps. I need to find the max value of column 3 from each timestep, fetch the corresponding row and put the row in a new matrix where the row index is same as the timestep index of the 3D matrix.
for k=1:30
[~,idx]=max(Once_Still_3D(:,3,k));
Out(k,:)=Once_Still_3D(idx,:,k);
end
Using this code results in repetition of values found with k=1 in the output file Out.
Here's the output:
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
Kindly help.
  2 Commenti
Sindar
Sindar il 20 Gen 2020
To me, this looks like it should work. I'd check your data. Does Once_Still_3D(:,3,1) look different from Once_Still_3D(:,3,2)?
Arup Bhattacharya
Arup Bhattacharya il 20 Gen 2020
Yes, matrices for all the timesteps are different. I am also trying to figure this out whether there is a problem with the 3D matrix or whether the max values everywhere is same.

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KSSV
KSSV il 20 Gen 2020
A = rand(68,8,30) ; % randmom data for demo
col = 3 ; % third column from which max to be seeked
[m,n,p] =size(A) ; % dimensions
iwant = zeros(p,n) ; % initialze the required
for i = 1:p
[val,id] = max(A(:,3,i)) ;
iwant(i,:) = A(id,:,i) ;
end

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