I wrote a function for a math formula, may I ask you please check my code?
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Hey all,
For my research, I needed to calculate some formula, So I searched everywhere, including Matlab file exchange and find nothing about the formula that I needed. Hence I decided to write a function for them and use them in my code. This is the very first time for me to write a function and also the first time to write a math formula. May I please ask you to check if where I do wrong?
Here is the formula:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/271788/image.jpeg)
And here is the function I wrote (I considered O as x and M as y):
function index_agreement = indexagreement(x,y)
%In the name of God - This function calculate
% Detailed explanation goes here
A = sum((y-x).^2);
B = abs(y - (mean(x)));
C = x - abs((mean(x)));
D = sum((B+C).^2);
index_agreement = 1 - (D);
end
Description: I run this function successfully, but I'm not sure about results because I believe they are not reasonable.
I want to thank you all.
Best Regards
0 Commenti
Risposta accettata
Image Analyst
il 15 Feb 2020
Assuming vertical bars mean absolute value and not modulus...
You got C wrong. Try
C = abs(x - abs((mean(x)));
then you need
index_agreement = 1 - abs(A / D);
There may be more errors, but I stopped looking once I found those errors.
5 Commenti
Image Analyst
il 16 Feb 2020
I thought it was weird because it should be positive already, but I just saw the vertical lines on either side of the fraction so I just said to do abs. If they are brackets, then I didn't notice the little "feet" on the bottom of the brackets, and the top ones are missing because your image clipped them off. But, no, you do not need the abs().
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Graphics Object Programming in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!