# I need help with my While Loop!

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Uma Dixit il 23 Feb 2020
Commentato: darova il 26 Feb 2020
I have an original array (3D) called 'pixelArray' that I eventually need to crop 3 different ways. So I have 3 different sets of x1,x2,y1,y2 numbers that crop the original array in different ways.
I currently have it set up like this:
x1 = [52, 52, 52];
x2 = [480, 480, 480];
y1 = [4, 1, 205] ;
y2 = [392, 205, 392];
n = 1;
while n < 3
%crop rows
pixelArray(1:y1(n),:,:)=[];
pixelArray(y2(n):end,:,:) = [];
%crop columns
pixelArray(:,1:x1(n),:)=[];
pixelArray(:,x2(n):end,:)=[];
n =n+1;
end
But I want to save each iteration's new pixelArray as its own matrix. What is the best way to go about doing this?
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Uma Dixit il 26 Feb 2020
Oh, very good point. How do you suggest I make sure the original pixelArray matrix stays intact in its dimensions?
darova il 26 Feb 2020
Remove elements from the end?
>> a = 1:10
a =
Columns 1 through 9
1 2 3 4 5 6 7 8 9
Column 10
10
>> a(7:9) = []
a =
1 2 3 4 5 6 10
>> a(1:3) = []
a =
4 5 6 10

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### Risposta accettata

Jakob B. Nielsen il 24 Feb 2020
Modificato: Jakob B. Nielsen il 24 Feb 2020
Index them! Either as a structure, or an array with a 4th dimension. I personally favour structures, since 4D data makes my head hurt ;) dot indexing is great for looping results.
Also note that you will only get 2 runs of your loop, as after the 2nd run n will equal 3, and your loop terminates before running a 3rd time since the condition is less than 3. Either make the condition less than or equal to 3, or you can use a for loop instead, as your while loop is essentially a for loop where you do the counting yourself - something you dont need to do in this case.
for n=1:3
%crop rows
pixelArray(1:y1(n),:,:)=[];
pixelArray(y2(n):end,:,:) = [];
%crop columns
pixelArray(:,1:x1(n),:)=[];
pixelArray(:,x2(n):end,:)=[];
Crops(n).pixelArray=pixelArray;
end
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