Reordering string arrays if string is >9

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Jason
Jason il 18 Mar 2020
Commentato: Jason il 18 Mar 2020
Hello, I have a string array that has been sorted but puts 10 next to 1
b =
1×6 string array
"1" "10" "3" "5" "7" "r1"
My strings are upto 12.
I want the last element to remain where it is, and to move any strings > 9 if exist to the end -1
i.e.
"1" "3" "5" "7" "10" "r1"
and if I have
"1" "10" "12" "5" "7" "r1"
then to be
"1" "5" "7" "10" "12" "r1"
This is my attempt:
b
Id10 = find(contains(b,"10"))
if Id10>0
e=b(Id10); b(Id10)=[]; b(end-1)=e;
out{j,1}=b;
b
end
Id11 = find(contains(b,"11"))
if Id11>0
e=b(Id11); b(Id11)=[]; b(end-1)=e;
out{j,1}=b;
b
end
Id12 = find(contains(b,"12"))
if Id12>0
e=b(Id12); b(Id12)=[]; b(end-1)=e;
out{j,1}=b;
end
b
but it seems to be over writing the end-1 element
b =
1×7 string array
"1" "10" "11" "12" "3" "6" "r1"
Id10 =
2
b =
1×6 string array
"1" "11" "12" "3" "10" "r1"
Id11 =
2
b =
1×5 string array
"1" "12" "3" "11" "r1"
Id12 =
2
b =
1×4 string array
"1" "3" "12" "r1"
Thanks for any help
  2 Commenti
BobH
BobH il 18 Mar 2020
This statement shortens the array (same for Id11/12)
b(Id10)=[];
All you were missing is a statement to restore the size, by copying the last element onto the end.
Then you could overwrite end-1
b(end+1) = b(end); % copy last element onto end
b(Id10)=[]; % remove '10'
b(end-1) = e; % overwrite end-1
Jason
Jason il 18 Mar 2020
Perfect, thankyou very much!

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Risposta accettata

BobH
BobH il 18 Mar 2020
sort_nat is powerful, and has helped me several times.
An alternative for simple number/not-number values is straightforward
  1. find the locations of the numbers
  2. sort those
  3. append the not-numbers
z = cellfun(@(X) logical(~isempty(str2num(X))),b); % z shows locations of number strings
n = cellfun(@str2num, b(z)); % into numerical
[~, ix] = sort( n ); % ix tells what order to pull from b
r = b(ix); % fill the result using sorted numbers
r{end+1} = b{~z}; % append the not-numbers
  6 Commenti
Jason
Jason il 18 Mar 2020
Thanks Bob, that will always be the case for me
BobH
BobH il 18 Mar 2020
Just for completeness, for those who might have numbers anywhere, here's a more general solution
  1. find the locations of the numbers
  2. build a new numeric vector, using a placeholder number for the not-numbers. Inf or -Inf are good choices that will sort to the end or the front
  3. use the sort index to pull from b
z = cellfun(@(X) logical(~isempty(str2num(X))),b); % z shows locations of number strings
n(~z) = Inf; % placeholder value; makes not-strings sort to end
n(z) = cellfun(@str2num, b(z));
[~, ix] = sort( n );
r = b(ix);

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Più risposte (1)

dpb
dpb il 18 Mar 2020
  1 Commento
Jason
Jason il 18 Mar 2020
Thanks, but Im running into an error
b =
1×6 string array
"1" "3" "6" "8" "9" "r1"
Index in position 1 exceeds array bounds.
Error in sort_nat (line 62)
num_val(i,z(i,:)) = sscanf(sprintf('%s ',digruns{i}{:}),'%f');
Error in PlateSeq2JB/LockPositionsButtonPushed (line 693)
[b,~] = sort_nat(b)

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