Need Help to find the error

6 visualizzazioni (ultimi 30 giorni)
Alex
Alex il 21 Ott 2012
Hello, I need from an array consisting of 10,000 items and are the coordinates (X and Y) of the ellipse to determine the minimum and maximum distance between two points. The problem is that the origin of 10000 should have 9999 range, the mine, the program calculates only 9998. you can verify using the command size(dist).
clear all
clc
A=[2/3 -2/3; 2/3 7/3];
[eigenvektor, eigenvalue]=eig(A);
n = 10000;
theta = linspace(0,2*pi,n);
r = 1;
x =r.*cos(theta);
y =r.*sin(theta);
plot(x,y,'.')
v = [x;y];
w=A*v;
xcoor=w(1,:);
ycoor=w(2,:);
i=0;
while i<n
i=i+1;
dxx2=xcoor(n-i:length(xcoor)-i);
dxx1=xcoor(n-(i+1):length(xcoor)-(i+1));
dyy2=xcoor(n-i:length(ycoor)-i);
dyy1=xcoor(n-(i+1):length(ycoor)-(i+1));
dist(i)=sqrt( (dxx2-dxx1)^2 + (dyy2-dyy1)^2);
end
  2 Commenti
Azzi Abdelmalek
Azzi Abdelmalek il 21 Ott 2012
which distance do you want, maybe there is a better way to do it
Alex
Alex il 21 Ott 2012
distance between two points of the ellipse. The circumference of an ellipse has 10 000 points. maxdistance=max(dist) maxdistance =0.0008378
mindistance=min(dist) mindistance = 6.581D-08 The formula for the distance set me right. The problem is that in its cycle, I do not get to a end of the array.

Accedi per commentare.

Risposta accettata

Azzi Abdelmalek
Azzi Abdelmalek il 21 Ott 2012
Modificato: Azzi Abdelmalek il 21 Ott 2012
r = 1;
x =r.*cos(theta);
y =r.*sin(theta);
plot(x,y,'.')
v = [x;y];
w=A*v;
xcoor=w(1,:);
ycoor=w(2,:);
figure,plot(xcoor,ycoor)
dist=sqrt(xcoor.^2+ycoor.^2)*2
min(dist)
max(dist)
If the origin of your ellipse is not (0,0) we can make translation
Also you don't need 10000 points, 5000 points are enough
dist=sqrt(xcoor(1:5000).^2+ycoor(1:5000).^2)
  3 Commenti
Azzi Abdelmalek
Azzi Abdelmalek il 21 Ott 2012
Modificato: Azzi Abdelmalek il 21 Ott 2012
do you want the distance between two consecutive points?
then look at Star's answer
Alex
Alex il 21 Ott 2012
thank you very much:)

Accedi per commentare.

Più risposte (1)

Star Strider
Star Strider il 21 Ott 2012
Instead of your while loop, I suggest:
dxx = diff(xcoor);
dyy = diff(ycoor);
dist = hypot( dxx, dyy);
Does this do what you want?

Categorie

Scopri di più su Creating and Concatenating Matrices in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by