- Vertically concatenating matrices with different numbers of rows, or
- Horizontally concatenating matrices with different numbers of columns.
How to fix a matrix?Dimensions of arrays being concatenated are not consistent
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I have a problem with the matrix dimension in my code:
I just want to calculate the average at the end of the code. This code actually works with the all the matrices(a big table of double) I have used before. However now I am struggling with this one table called UgisM0L06, that I will also upload. I dont understand how can I fix the fact that the matrix "L_PeaksM0L06 ", resulting from the last FOR LOOP ,does not give the same number of elements for each column.
I will upload also the table of doubles UgisM0L06.
Please, any help would be appreciated. let me know if something is not cler.
CODE:
% Shoes UgisM0L06
L_3=UgisM0L06(:,1:99);
% D_18(1:15,32)=[0];
mask = sum(L_3, 2)~=0;
comps = bwconncomp(mask);
compMaskList = comps.PixelIdxList; %chunks positions(steps rows)
L_3_components = cell(numel(compMaskList), 1);
for i=1:numel(compMaskList)
step{i} = L_3(compMaskList{i}, :);
if size(step{i})<=[30 99]
step{i}=[];
end
end
n_steps=step(~cellfun('isempty',step));
% n_steps=[step(1:2),step(8:10),step(13:19)];
if length(n_steps)>=12
steps=n_steps(1:12);
size(steps)
end
for i=1:length(n_steps)
Big_ToeM0L06{i}=[n_steps{i}(:,[83:84]),n_steps{i}(:,[90:91]),n_steps{i}(:,96)];
Peak_HalluxM0L06(i) = max(Big_ToeM0L06{i}, [], 'all');
Other_ToesM0L06{i}=[n_steps{i}(:,[81:82]),n_steps{i}(:,[85:89]),n_steps{i}(:,[92:95]),n_steps{i}(:,[97:99])];
Peak_PhalangesM0L06(i)=max(Other_ToesM0L06{i}, [], 'all');
MedFM0L06{i}=[n_steps{i}(:,[62:63]),n_steps{i}(:,[69:70]),n_steps{i}(:,[76:77])];
Peak_Mtpj1M0L06(i)=max(MedFM0L06{i}, [], 'all');
C_FM0L06{i}=[n_steps{i}(:,[64:66]),n_steps{i}(:,[71:73]),n_steps{i}(:,[78:80])];
Peak_Mtpj23M0L06(i)=max(C_FM0L06{i}, [], 'all');
LatFM0L06{i}=[n_steps{i}(:,[60:61]),n_steps{i}(:,[67:68]),n_steps{i}(:,[74:75])];
Peak_Mtpj45M0L06(i)=max(LatFM0L06{i}, [], 'all')
end
L_PeaksM0L06=[Peak_HalluxM0L06',Peak_PhalangesM0L06',Peak_Mtpj1M0L06',Peak_Mtpj23M0L06',Peak_Mtpj45M0L06'];
for j=1:5
AverageM0L06(j) =mean(L_PeaksM0L06(:,j));
end
AveragesM0L06=[AverageM0L06]
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Risposte (1)
Image Analyst
il 13 Mag 2020
I didn't run your code but usually "Dimensions of arrays being concatenated are not consistent" means that you are stitching/concatenating things of different sizes. For example, you are
Example for case 1
1 2
3 4
cannot be concatenated with
1 2 3
3 4 5
because column 3 cannot be blank in rows 1 and 2.
Which is your situation?
Actually, I almost just repeated the FAQ: https://matlab.fandom.com/wiki/FAQ#.E2.80.9CDimensions_of_arrays_being_concatenated_are_not_consistent..E2.80.9D
3 Commenti
Image Analyst
il 14 Mag 2020
You can do this:
B=[1;1]
C=[2;2]
D=[3;3]
A = [B, C, D]
B =
1
1
C =
2
2
D =
3
3
A =
1 2 3
1 2 3
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