I want to repeat this code 32 times and each time stores the result to get matrix 1*32

counter=0;
for i=1:256
    for j= 1:256
        if L(i,j) == k
           counter= counter+1;
        end 
    end 
end

Answer 1

[Geoff Hayes]

Osama - presumably you want to store the counter value from each of the 32 iterations so you could do something like

n = 32;
counter = zeros(n,1);
for m = 1:n
    for i=1:256
        for j= 1:256
            if L(i,j) == k
               counter(m) = counter(m) + 1;
            end 
        end 
    end
end

I'm assuming that there is some missing code since the above will produce the same result (i.e. all elements of counter will be identical) for each of the 32 iterations.

[Osama Dwairi]

thanks , its working