Specifying a range in a double

% Values is a 401x1 double: 1 - 401
% In this example, I want to take the mean from Values(90) to Values(110).

% Specify Bounds
MAX = 90; % 
MIN = 110;
idy = find(Values == MIN);
idz = find(Values == MAX);
Values = mean(Values(idy:idz));

This is simple & should be returning 1 number from Values after taking the mean, but it's resulting in a 1x7^6 double.

Is there a syntax error that I'm overlooking here?

[Fangjun Jiang]

code is simple enough. run the code line by line and see where is wrong.

The numerical value for MAX and MIN seems to be reversed. Is that correct?

Answer 1

[William Alberg]

I think, that you want to do this:

MAX = 110;
MIN = 90;
id = find( (MIN <= Values) & (Values <= MAX) )
Values = mean(Values(id))

I switched the MIN/MAX values

[Keith Grey]

Ah, I see what I did now! The MAX value was lower than the MIN, so of course the computer's going to hate that. Thank you very much!