How to write piecewise function in matlab for the following function. Please give me matlab code.
4 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
soe min aung
il 14 Giu 2020
Commentato: Star Strider
il 14 Giu 2020
clc
clear all
close all
syms x y
zeta0 = 0.5
L = 100;
W = 100;
h = 2;
g = 0.0098;
vt=sqrt(g*h)
c=1
v=c*vt
t1 = L/v
t = t1;
T1 = zeta0*v*t/(2*L)*(1-cos(pi/50*x)).*(1-cos(pi/100*(y+150))) ;
T2 = zeta0*v*t/L*(1-cos(pi/50*x)) ;
T3 = zeta0*v*t/(2*L)*(1-cos(pi/50*x)).*(1-cos(pi/100*(y-150))) ;
T = piecewise(0<=x<=100 , -150<=y<=-50, T1, 0<=x<=100 , -50<=y<=50, T2,0<=x<=100 , 50<=y<=150, T3)
fplot(T)
0 Commenti
Risposta accettata
Star Strider
il 14 Giu 2020
Creating an anonymous function for ‘T’ is much easier and faster than using piecwise and the Symbolic Math Toolbox for this:
zeta0 = 0.5
L = 100;
W = 100;
h = 2;
g = 0.0098;
vt=sqrt(g*h);
c=1;
v=c*vt;
t1 = L/v;
t = t1;
T1 = @(x,y) zeta0*v*t/(2*L)*(1-cos(pi/50*x)).*(1-cos(pi/100*(y+150))) ;
T2 = @(x,y) zeta0*v*t/L*(1-cos(pi/50*x)) ;
T3 = @(x,y) zeta0*v*t/(2*L)*(1-cos(pi/50*x)).*(1-cos(pi/100*(y-150))) ;
T = @(x,y) ((0<=x) & (x<=100) & (-150<=y) & (y<=-50)).*T1(x,y) + ((0<=x) & (x<=100) & (-50<=y) & (y<=50)).*T2(x,y) + ((0<=x) & (x<=100) & (50<=y) & (y<=150)).*T3(x,y);
[X,Y] = ndgrid(-100:5:200);
figure
surf(X,Y,T(X,Y))
grid on
.
2 Commenti
Più risposte (1)
Aditya Verma
il 14 Giu 2020
Modificato: Aditya Verma
il 14 Giu 2020
Hello there!
You can code a piecewise function using conditional statements. More specifically, using if-else clause in this case. An example of absolute value function would be:
function val = absVal(x)
if x >= 0
val = x;
else
val = -x;
end
end
In a similar way, you can code your function.
If you are new to this concept, I recommend you to take the free MATLAB Onramp course, it will help you to get started with MATLAB.
UPDATE
If you have Symbolic Math Toolbox, you can use it to define this function in a similar way as you have mentioned. You can find similar examples here: https://www.mathworks.com/help/symbolic/piecewise.html#bu_gw85-1.
0 Commenti
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!