How can i find the maximum of three variables?

Hi, I have to find the maximum of three variables A, B, C and store the result in D. thanks

2 Commenti

use max. d=max(a,b,c)
Have you tried this, Sara?
d = max(2,3,4)
According to the help text this fails.

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Risposte (5)

D=max([A,B,C]);

2 Commenti

I assume, this is a homework question.
I suppose. Can't be worth more than 1 point, though...

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How would you find the maximum of two variables?
docserach maximum
Then if you have the maximum of two variables, you can compare it to the third one.
pshymn
pshymn il 13 Apr 2017
Modificato: pshymn il 13 Apr 2017
maybe, i am a little late, but i experienced the same problem. here is my solution. it works, tried. function which finds maximum of three variable.
function [p] = MAX(g,h,j)
if g>h && g>j
p=g;
elseif h>g && h>j
p=h;
else
p=j;
end

1 Commento

That code assumes scalar values. It also assumes no nan values.

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In general, for A, B, and C being numerical arrays of any size (possibly different than each other):
% Define 3 double matrixes of different sizes
A = rand(3);
B = rand(4);
C = rand(5);
% Now get the max overall
D = max([A(:), B(:), C(:)]) % Note use of (:) to turn arrays into vectors.
If they're cell arrays or structures though, let us know because that would be different.

1 Commento

If A, B, C hav different sizes, [A(:), B(:), C(:)] fails. But [A(:); B(:); C(:)] with the semicolons for vertical concatenation works.

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Sarah Crimi
Sarah Crimi il 5 Ott 2018
Modificato: Sarah Crimi il 5 Ott 2018
if it is vectors of different sizes, you would have to do max(max(a),max(b)),max(max(b),max(c)). So, it takes max of the first and second vectors and compares the values, and max of the second and third vectors, then takes the max of those two numbers.

2 Commenti

"if it is vectors of different sizes you would have to do..."
Or you can just call max once (as Jan Simon showed earlier):
max([a(:);b(:);c(:)])
Sarah Crimi
Sarah Crimi il 16 Nov 2018
Modificato: Sarah Crimi il 16 Nov 2018
Oh yes, I see. This makes it into one vector then takes the max.

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Richiesto:

il 27 Nov 2012

Modificato:

il 16 Nov 2018

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