Azzera filtri
Azzera filtri

Could you help me with the simplification of these kind of results?

2 visualizzazioni (ultimi 30 giorni)
Really, I don't understand why Matlab is so horrible at making a decent simplification of fractions:
Look at this:
For example, the first result is just this:
How can I get a better simplification of these kind of results? I've tried simplify + other commands but just can't, it doesn't work
  1 Commento
John D'Errico
John D'Errico il 29 Giu 2020
Modificato: John D'Errico il 29 Giu 2020
How many times will you ask the same question? How is this question fundamentally different from the last time you asked it?
That you think 1/sqrt(2) is simpler than sqrt(2)/2, is just your personal preference, a choice made by you, but apparently not preferred by symengine.
1/sqrt(sym(2))
ans =
2^(1/2)/2
I expect we will hear again, asking about a truly novel problem, like 1/sqrt(3).
Thankfully, you may give up by the time we get to 4.
1/sqrt(sym(4))
ans =
1/2

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Risposte (1)

Walter Roberson
Walter Roberson il 29 Giu 2020
Did you simplify() telling it to ignore analytic constraints?
If p0 is 0 then the expression to the power 0 would be 0^0 which is undefined. If you put in a constraint that forces p0 to be nonzero and m to be finite then the power 0 could be simplified.
  1 Commento
Walter Roberson
Walter Roberson il 29 Giu 2020
Ah, is that a list of three different values, or is it a single expression that continues over multiple lines with the second term of the subtraction being raised to power 0?

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