Add cut line (horizontal line) in bar graph

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Dionisio Mendoza il 30 Giu 2020
Commentato: Image Analyst il 20 Set 2022
Hello everybody.
I just made a bar graph using the bar function, but I want a horizontal line to appear on the x axis. I know the xline function exists, but my MATLAB version appears to be old. Below I show the simple code.
x = [3.10,8.17,9.84,4.71,1.43,6.90,3.70,10.24,9.61,5.92,4.51,7.12,2.99,4.73,5.96,9.58,7.22,4.91,4.80,8.79,8.45,6.38,2.83,1.10,7.47,5.36,10.42,5.11,5.15,4.25,7.65,7.05,3.60,4.08,7.29,4.72,4.90,8.74,5.42,9.96,4.88,4.06,4.68,6.67,4.16,6.20,7.34,2.96,7.16,6.34,9.20,4.66,7.42,3.32,8.45,5.59,4.97,5.50,6.20,1.30,3.84,3.97,7.98,6.71,5.26,6.39,6.24,9.19,9.27,4.63,7.20,7.45,4.94,7.57,6.79,8.58,6.51,5.98,5.44,5.47,6.67,5.33,7.59,5.82,4.24,2.86,3.14,4.93,4.15,4.58,7.20,5.33,4.17,6.30];
bar(x,0.8,'w');
ylabel('volume')
xlabel('Pacients')
xticks([1:94]);
yticks([1:11]);
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Image Analyst il 30 Giu 2020
Modificato: Image Analyst il 30 Giu 2020
Horizontal line on the x axis. What does that mean? The x axis is already horizontal so the line would overlap it. Do you mean horizontal line parallel with the x axis, intersecting the y axis at some value? xline() gives a vertical line, not a horizontal line. So we're not sure what you want. So I'm doing it both ways:
x = [3.10,8.17,9.84,4.71,1.43,6.90,3.70,10.24,9.61,5.92,4.51,7.12,2.99,4.73,5.96,9.58,7.22,4.91,4.80,8.79,8.45,6.38,2.83,1.10,7.47,5.36,10.42,5.11,5.15,4.25,7.65,7.05,3.60,4.08,7.29,4.72,4.90,8.74,5.42,9.96,4.88,4.06,4.68,6.67,4.16,6.20,7.34,2.96,7.16,6.34,9.20,4.66,7.42,3.32,8.45,5.59,4.97,5.50,6.20,1.30,3.84,3.97,7.98,6.71,5.26,6.39,6.24,9.19,9.27,4.63,7.20,7.45,4.94,7.57,6.79,8.58,6.51,5.98,5.44,5.47,6.67,5.33,7.59,5.82,4.24,2.86,3.14,4.93,4.15,4.58,7.20,5.33,4.17,6.30];
bar(x,0.8,'w');
ylabel('volume')
xlabel('Pacients')
xticks([1 : 10 : 94]);
yticks([1 : 11]);
grid on;
% Draw a vertical line at x = 50;
line([50, 50], ylim, 'Color', 'm', 'LineWidth', 2);
% Draw a horizontal line at y = 6;
line(xlim, [6, 6], 'Color', 'r', 'LineWidth', 2);
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Lavanya il 20 Set 2022
Ok, I will try to explain in a better way. As shown in 'image1.jpg', by using the ginput() , able to select the coordinates and using xline it's appearing as blue line. My question is If I want to try the ginput values manually( By using Editfield) the coordinates from the graph. Is it possible to that?
For example:
If I will give x=0.001,y = 12, from the edit field, 'image1.jpg', 1st blue line should appear.
Image Analyst il 20 Set 2022
Yes, does it not do that? Where did it draw the line when you ran my code. Perhaps start your own discussion thread.

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Duijnhouwer il 30 Giu 2020
Modificato: Duijnhouwer il 30 Giu 2020
hold on
plot(xlim,[5 5],'r-','LineWidth',2)
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Dionisio Mendoza il 1 Lug 2020
Thanks for the help :).

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