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Move-File: Can't move certain Files to another Folder!

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Hello! I want to extract some Files based on a certain criteria (here: bytes < 70 000 000). But I don't get it to work, some Ideas?
This is my approach so far..
files_zum_Testen = dir('...\MOVE_MDF\*.mf4');
move_bedingung = [files_zum_Testen.bytes] < 70000000;
move_list = fullfile({files_zum_Testen(move_bedingung).folder}, {files_zum_Testen(move_bedingung).name});
movefile (move_list, newFolder)

  1 Comment

Stephen Cobeldick
Stephen Cobeldick on 6 Jul 2020
You will need to use a loop, and move each file separately.
The movefile documentation describes its source input as one character vector or string scalar, It does not state that the source can be a cell array of character vectors or a non-scalar string.
It states that multiple files can be matched using the wildcard *. But because you want to match on some other property (not using a wildcard) you will have to call movefile for each file.

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Accepted Answer

Geoff Hayes
Geoff Hayes on 6 Jul 2020
Malte - you haven't posted the error message or describe fully what you mean by I don't get it to work. According to movefile input arguments, the source is a character vector corresponding to a single file or directory. I don't think that passing in a cell array (list of files) will work and so you will need to move each file individually.


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Malte Räuchle
Malte Räuchle on 7 Jul 2020
If I do it like this:
movefile(sourceFileName, '...\newFolder')
only 1 File is moving to the newFolder, but the correct result would be 2 Files. And the error: Error using fullfile - Not enough input arguments occurs. And I have no explanation for it..
Stephen Cobeldick
Stephen Cobeldick on 7 Jul 2020
"And I have no explanation for it.."
Your approach means that when the logical scalar fileToMove is false then you are generating comma-separated lists with zero outputs, and so fullfile has zero input arguments. That causes the error. While you could make this approach work (e.g. use if and you need to use index k rather than a logical scalar to select from files_zum_Testen) it would likely be simpler and clearer to use the logical array to filter the required files before the loop, e.g.:
D = '...\MOVE_MDF';
S = dir(fullfile(D,'*.mf4'));
X = [S.bytes] < 70000000;
C = {S(X).name}; % filter here!
for k = 1:numel(C)
F = fullfile(D,C{k});
movefile(F, newFolder)
Malte Räuchle
Malte Räuchle on 7 Jul 2020
Thank you all for your help. I'm new to matlab and still learning.. A combination of both answers was a good solution and exactly what I needed!!
Appreciate it!

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