MATLAB code for right handed circular polarization
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Hello, I need help to write simple code that preview right handed circular polarization, using the cos and sin fun. also in the plot must see the direction of the polarization (for example with arrows).
the expression of RHCP is : Acos(t)+Asint(t)
2 Commenti
Walter Roberson
il 14 Dic 2012
To check: is Acos(t) to mean arccosine of t, or is it to mean A multiplied by cosine of t ? Is Asint intended to mean A times sine (of something?) times (t applied to t) ??
Risposte (3)
Image Analyst
il 14 Dic 2012
You mean like this: ???
fontSize = 20;
A = 10; % Amplitude.
t = linspace(0, 2 * pi, 40);
signal = A .* cos(t) + A .* sin(t);
stem(t, signal, 'bo-', 'LineWidth', 2);
xlabel('t', 'FontSize', fontSize);
ylabel('signal', 'FontSize', fontSize);
title('RHCP', 'FontSize', fontSize);
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
% Give a name to the title bar.
set(gcf,'name','Demo by ImageAnalyst','numbertitle','off')
1 Commento
Walter Roberson
il 14 Dic 2012
A .* cos(t) + A .* sin(t) could be simplified to A .* (cos(t) + sin(t))
Bjorn Gustavsson
il 18 Dic 2012
That it is possible to rewrite A*cos(t) + A*sin(t) to A*(cos(t)+sin(t)) clearly shows that that is a scalar quantity - such has by definition no polarization. Try instead with something that is a vector-valued function:
A*[cos(w*t-kz),-sin(w*t-k*z),0]
0 Commenti
AbdulRehman Khan Abkhan
il 16 Nov 2021
A = 10; % Amplitude.
t = linspace(0, 2 * pi, 40);
signal = A .* cos(t) + A .* sin(t);
stem(t, signal, 'bo-', 'LineWidth', 2);
x('t');
y('signal');
title('RHCP');
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
% Give a name to the title bar.
set(gcf,'name','Demo by ImageAnalyst','numbertitle','off')
1 Commento
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