Reference to non-existent field 'i'.

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%% To Create Symbolic symmentric P matrix of Order n*n
n=2;
%n=3;
p_n=(n*(n+1))/2;
P = sym('a', [n n],'real');
P_list = sym('p', [1 p_n],'real');
%logic to generate the Matrix
index=1;
for i=1:n
for j=1:n
if(i<=j)
P(i,j)=P_list(index);
index=index+1;
else
P(i,j)=P(j,i);
end
end
end
P
%% To Create symbolic A in CCF form
%Logic to generate A matrix(In controllable canonical form)
A_list = sym('a', [1 n],'real');
A_list = -A_list;
A=zeros(n-1,n);
for i=1:(n-1)
for j=1:n
if j==i+1
A(i,j)=1;
end
end
end
A=[A ; A_list];
A
%% Solve the symbolic equation using traditional method
% Solving Lyapunov equation symbollicaly
% Uses above generated A and P Matrix
Q_N=-eye(n);
Condition=A'*P + P*A;
Eq=Condition==Q_N;
eqns=[Eq(:)];
vars = P_list;
S = solve(eqns,vars,'Real',true);
%% Display results
%Extracting values from structure S
p1=S.p1
p2=S.p2
p3=S.p3
% p4=S.p4
% p5=S.p5
% p6=S.p6
I am trying to make the above extraction of fields [p1 p2 p3 ....] from structure S to work for any value(integer) of n instead of hardcoding everytime as I doing currently.
I tried with for loop as below but getting the error Reference to non-existent field 'i'.
Is there any way to achieve the task of extraction of fields from Struct (Symbolic Data Type) without hardcoding.
%% Generic way to Display result
%**************THIS SESSION IS CREATING ERROR************************
%n=2 has P_list=[p1,p2,p3]
%n=3 has P_list=[p1,p2,p3,p4,p5,p6]
%n=4 has P_list=[p1,p2,p3,p4,p5,p6,p7,p8,p9,p10]
for i=P_list
i=S.i
end
  2 Commenti
KSSV
KSSV il 20 Lug 2020
Clearly there S do not have i as a field.
KESAVKUMAR A
KESAVKUMAR A il 21 Lug 2020
Thanks for response.
Yes you are right i is not a field in S but when it is assigned to P_list and itterated as below
i got ans as
i=p1
i=p2
i=p3
So tried using S.i inside for loop and got error Reference to non-existent field 'i'.I am confused what does this mean.
for i=P_list
i
end

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Risposta accettata

Walter Roberson
Walter Roberson il 21 Lug 2020
S.(char(P_list(i)))
  3 Commenti
Walter Roberson
Walter Roberson il 21 Lug 2020
After the first iteration you have replaced the function named char with an array named char
In MATLAB it is never possible to compute the name of the output variable in a direct assignment statement. Basically... Don't Do That, it doesn't end well in the long run.
KESAVKUMAR A
KESAVKUMAR A il 21 Lug 2020
Thanks.That helps!!!!

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Più risposte (1)

KSSV
KSSV il 20 Lug 2020
Modificato: KSSV il 20 Lug 2020
Read about getfield.
for i=1:length(P_list)
val = getfield(S,P_list{i})
end
  3 Commenti
KSSV
KSSV il 21 Lug 2020
S.a = rand ;
S.b = rand ;
S.c = rand ;
P_list = fieldnames(S) ;
for i = 1:length(P_list)
val = getfield(S,P_list{i})
end
KESAVKUMAR A
KESAVKUMAR A il 21 Lug 2020
Thanks.This answer is also acceptable.

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