Histogram with log Bin width

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Markus Similä
Markus Similä il 3 Ago 2020
Modificato: Markus Similä il 6 Ago 2020
I have a single column vector with values ranging from 0 to about 400 000.
I need to make a histogram from this data, which has a logarithmically changing bin size.
The height values in each bin should also be divided with the corresponding bins width.
How can this be done?
Advice would be appreciated,
Thanks

Risposta accettata

Sean de Wolski
Sean de Wolski il 3 Ago 2020
x = rand(1,10000)*100000;
bins = 10.^(0:5);
histogram(x, bins);
set(gca, "XScale", "log")
  1 Commento
Markus Similä
Markus Similä il 4 Ago 2020
Thanks!
This sort of works. But does it divide the values by the width of each bin?

Accedi per commentare.

Più risposte (1)

Markus Similä
Markus Similä il 6 Ago 2020
Modificato: Markus Similä il 6 Ago 2020
edges = 10.^(1:0.01:6);
[N,edges] = histcounts(x,edges,'Normalization','countdensity');
g = histogram('BinEdges',edges,'BinCounts',N);
set(gca, "Xscale", "log")
set(gca, "YScale", "log")
Allright, I'm going to answer my own question.
x is your data.
'countdensity' normalizes the data exactly how you want.
Make sure that the histogram command doesn't bin your data anymore,
as you have done it already in histcounts. :D

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