Info
Questa domanda è chiusa. Riaprila per modificarla o per rispondere.
Unusual size of array
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
close all;
clc;
clear;
sobj=sparameters('W=2um_L=20um.s2p');
s=sobj.Parameters;
freq=sobj.Frequencies;
y_params = s2y(s);
y11=y_params(1,1,:);
y12=y_params(1,2,:);
y21=y_params(2,1,:);
y22=y_params(2,2,:);
Ca=(imag(y11+y12))./(2*pi.*freq);
Cb=(imag(y22+y21))./(2*pi.*freq);
R=real(-1/y21);
L=(imag(-1/y21))./(4*pi*freq);
In the code above I converted S parameter in s2p file attached to y parameters, and I am trying to to calculate some values from that. However for some reason the size of Ca, Cb and L arrays is unusual, according to me they should be 1D arrays with 201 values, however when calculated they come out to be 201X201 values.
Can someone point out the mistake in my code? I am very new to this, any optimisation and use of objects and how I am accesing y parameters, any improvement will be highly appreciated.
Thankyou in advance.
2 Commenti
David Hill
il 13 Ago 2020
You just need to examine the sizes of your arrays in your workspace. I suspect that freq matrix is a 201x201. Not sure how you want to handle it.
R=real(-1./y21);%I believe you need ./
L=(imag(-1./y21))./(4*pi*freq);%same here
Risposte (1)
Bruno Luong
il 17 Ago 2020
Try this
sobj=sparameters('W=2um_L=20um.s2p');
s=sobj.Parameters;
freq=sobj.Frequencies;
y_params = s2y(s);
y11=y_params(1,1,:);
y12=y_params(1,2,:);
y21=y_params(2,1,:);
y22=y_params(2,2,:);
Ca=(imag(y11(:)+y12(:)))./(2*pi.*freq(:));
Cb=(imag(y22(:)+y21(:)))./(2*pi.*freq(:));
R=real(-1./y21(:));
L=(imag(-1./y21(:)))./(4*pi*freq(:));
0 Commenti
Questa domanda è chiusa.
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!