Histogram to a CDF/PDF

65 visualizzazioni (ultimi 30 giorni)
Sclay748
Sclay748 il 24 Ago 2020
Commentato: Sclay748 il 24 Ago 2020
Hello, This is a screenshot of a table I have constructed for work.
Just to play it safe, I blacked out the column names, though it would be hard to assume anything with just 7 rows of the table to go off of. We will call the 5 fields "column1, column2, etc."
So I am able to create the hisogram of any of the columns, besides 3, but that isn't needed because it is all '94'.
I do:
histogram([a(1:135756).column1])
and the histogram works perfectly.
How would I do a CDF or PDF of this data?
I have tried:
histogram([a(1:135756).column1],'Normalization',pdf)
or
histogram([a(1:135756).column1],'Normalization',cdf)
but nothing changes from the original histogram.
Thank you!

Risposta accettata

Bruno Luong
Bruno Luong il 24 Ago 2020
Modificato: Bruno Luong il 24 Ago 2020
A=[a(1:135756).column1];
figure
subplot(2,1,1);
histogram(A,'Normalization','pdf');
ylabel('pdf');
subplot(2,1,2);
histogram(A,'Normalization','cdf');
ylabel('cdf');

Più risposte (1)

Alan Stevens
Alan Stevens il 24 Ago 2020
You can get a CDF as follows:
% Modified Kaplan-Meier CDF
% assumes each point is representative of 1/N of the population.
a = sort(a(:,1)); % so all the data for a are sorted in ascending order
N = length(a);
for k = 1:N
CDF(k) = (k - 0.5)/N;
end
plot(a,CDF)
Because you have a large number of points you could simply numerically differentiate the CDF to get a PDF.
  4 Commenti
Bruno Luong
Bruno Luong il 24 Ago 2020
Hmm it cries for replacing the for-loop
a1 = sort([a(1:135756).column1]);
N = length(a1);
CDF = (0.5:N-0.5) / N;
plot(a1, CDF);
Sclay748
Sclay748 il 24 Ago 2020
Modificato: Sclay748 il 24 Ago 2020
Bruno, that worked. Is it supposed to be a single curved line?
I thought it would still plot the bars, but arranged by CDF. Or that is atleast how my boss's turned out when he showed me an example using histogram(......,'Normalization',cdf)

Accedi per commentare.

Categorie

Scopri di più su Data Distribution Plots in Help Center e File Exchange

Prodotti


Release

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by