Calculate the energy of the signal, find odd and even component and then plot it.

2 visualizzazioni (ultimi 30 giorni)
This is what my teacher have told to me.
ONLY HOW TO CLACULATE ENERGY.
clc
clear all
close all
syms x t
x=exp(-2.^t);
z=x^2;
Energy=int(z,t,0,inf);
disp(Energy)
also want to plot the expnonential function, how can i do that for the above code?
This is what i have done.
clc
close all
clear all
%FOR ENERGY
t= 0:0.09:10;
p= -2.*t;
x= exp(p);
energy= 1/(2*2) % if e^-at is an energy signal⇒ energy = 1/2*a
subplot(2,1,1)
plot(t,x)
text(5,0.4, ['Energy Of The Signal =', num2str(energy)])
xlabel('time->')
ylabel('x(t)')
title('Plot For x(t)')
grid on
gtext('1841014009')
% FOR EVEN AND ODD COMPONENT
p2= -2.*-t;
x2= exp(p2);
xe= (x+x2)/2; % FOR EVEN
xo= (x-x2)/2; %FOR ODD
subplot(2,1,2);
plot(t,xe,'r')
hold on
plot(t,xo,'b')
legend ('EVEN','ODD')
xlabel('time->')
ylabel('x(t)')
grid on
gtext('1841014009')
please help me......
which one is the correct answer, first one or second one?
OR
both are wrong.

Risposta accettata

VBBV
VBBV il 31 Ott 2020
Modificato: VBBV il 31 Ott 2020
% if true
% code
% end
clc
syms x t
close all
x=exp(-2*t);
z=@(x) x.^2;
Energy=integral(z,0,inf);
%plot odd and even signals
t = 0:0.1:20;
x = exp(-2.*t);
xx = exp(-2.*-t);
xe= (x+xx)./2;
xo = (x-xx)./2;
plot(t,xo,'b',t,xe);legend('odd','even');
  1 Commento
Suraj Narayan
Suraj Narayan il 31 Ott 2020
Modificato: Suraj Narayan il 31 Ott 2020
Thanks for the help.
Could you please explain in more detail about the integral part
And is it possible to plot the signal.

Accedi per commentare.

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