Azzera filtri
Azzera filtri

image steganography using RGB image in matlab

4 visualizzazioni (ultimi 30 giorni)
prasanth
prasanth il 17 Feb 2013
Commentato: sruthi sruthi il 20 Ago 2019
I was working on image steganography of lsb substitution using RGB image.I couldn't able to figure out what's wrong in the code. It is not showing an error.But,the answer is different while retrieving and codes are :
Embbeding code:
clc
c = imread('pout.tif');
c=imresize(c,[64 64],'nearest');
message = 'image';
message = strtrim(message);
m = length(message) * 8;
AsciiCode = uint8(messag e);
binaryString = transpose(dec2bin(AsciiCode,8));
binaryString = binaryString(:);
N = length(binaryString);
b = zeros(N,1);
for k = 1:N
if(binaryString(k) == '1')
b(k) = 1;
else
b(k) = 0;
end
end
s = c;
height = size(c,1);
width = size(c,2);
k = 1;
for i = 1 : height
for j = 1 : width
LSB = mod(double(c(i,j)), 2);
if (k>m || LSB == b(k))
s(i,j) = c(i,j);
else
if(LSB == 1)
s(i,j) = (c(i,j) - 1);
else
s(i,j) = (c(i,j) + 1);
end
k = k + 1;
end
end
end
imwrite(s,'msgimage.tif');
imshow(c)
retrieving_code:
clc
s = imread('msgimage.bmp');
height = size(s,1);
width = size(s,2);
m = 64;
k = 1;
for i = 1 : height
for j = 1 : width
if (k <= m)
b(k) = mod(double(s(i,j)),2);
k = k + 1;
end
end
end
binaryVector = b;
binValues = [ 128 64 32 16 8 4 2 1 ];
binaryVector = binaryVector(:);
if mod(length(binaryVector),8) ~= 0
error('Length of binary vector must be a multiple of 8.');
end
binMatrix = reshape(binaryVector,8,8);
textString = char(binValues*binMatrix);
disp(textString);
help please.
  3 Commenti
SHALU SINGH
SHALU SINGH il 30 Mar 2014
i need this steganography code... will u give to me...??
HANIYAH FATIMA
HANIYAH FATIMA il 8 Dic 2018
after the retriving code,text string is not displayed

Accedi per commentare.

Risposte (1)

riyaz nadaf
riyaz nadaf il 26 Gen 2019
i did this project. if you want matlab code contact
riyaznadaf034@gmail.com
  1 Commento
sruthi sruthi
sruthi sruthi il 20 Ago 2019
sir!
i need the sourcecode for this project.
please help me in this sir....

Accedi per commentare.

Categorie

Scopri di più su Encryption / Cryptography in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by