Azzera filtri
Azzera filtri

OLS estimator b=x\y?

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TAEKYU EOM
TAEKYU EOM il 11 Nov 2020
Commentato: Star Strider il 11 Nov 2020
Hi guys,
when x is n*2 vector and y is n*1 vector,
b=(x'*x)^(-1)*x'*y.
If I use the expression like
b=x\y,
both have same results.
What is difference between these two expressions?

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Star Strider
Star Strider il 11 Nov 2020
What is difference between these two expressions?
The way they are implemented in MATLAB. The documentation for mldivide,\ explains how it works (so I won’t go into that here), and the reason it is more stable and preferred over taking the inverse and multiplying.
  2 Commenti
TAEKYU EOM
TAEKYU EOM il 11 Nov 2020
Thanks for your comment!
Star Strider
Star Strider il 11 Nov 2020
As always, my pleasure!

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