or() in categorical variable

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TAEKYU EOM
TAEKYU EOM il 23 Nov 2020
Commentato: TAEKYU EOM il 23 Nov 2020
I don't know why the results of index1 and index2 are different.
The variable
financial_status=[1,2,3,4,5];
index1 = find(financial_status==or(1,2));
index2 = find(financial_status>=1&financial_status<=2);
  2 Commenti
dpb
dpb il 23 Nov 2020
Because
>> or(1,2)
ans =
logical
1
>>
TAEKYU EOM
TAEKYU EOM il 23 Nov 2020
I got it, thanks!

Accedi per commentare.

Risposta accettata

dpb
dpb il 23 Nov 2020
Because
>> or(1,2)
ans =
logical
1
>>
You're apparently looking for
>> ismember(financial_status,[1,2])
ans =
1×5 logical array
1 1 0 0 0
>>
Rarely are the actual indices returned by find needed, but can be if this is one of those cases that simply using the logical addressing array isn't sufficient.

Più risposte (1)

Walter Roberson
Walter Roberson il 23 Nov 2020
Modificato: Walter Roberson il 23 Nov 2020
ismember(financial_status, 1:2)
At the moment I cannot think of any computer language that expresses a set membership test in terms of an equality test. Which computer language were you inspired by?

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