I'm getting the error "Array indices must be positive integers or logical values." and it seems like I structures the for loop to handle the equations. Can anyone help me with this?
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Matthew Williams
il 13 Dic 2020
Risposto: Gouri Chennuru
il 16 Dic 2020
ds=zeros(length(y),1);
dAs=zeros(length(y),1);
Ac=zeros(length(y),1);
for j=1:N
t1=(t(y(j))+t(y(j+1/2)))/2; %average thickness of CV on side closer to y=0
t2=(t(y(j-1/2))+t(y(j)))/2; %avgerage thickness of CV on side closer to y=L
ds(j)=sqrt((t(y(j+1))-t(t(j-1))).^2+(2*dy).^2)/2; %using central difference
dAs(j)= (w+((t1+t2)/L))*ds(j)*dx; %surface area
Ac(j)=(t(y(j)))*dx; %Cross sectional area
end
3 Commenti
Walter Roberson
il 13 Dic 2020
You cannot index at half-integers . You can index a value and divide the result by 2, though.
Risposta accettata
Gouri Chennuru
il 16 Dic 2020
Hi Matthew,
As per my understanding, you are trying to extract the variable "y" with indices (j+1/2) and (j-1/2), from the following lines.
t1=(t(y(j))+t(y(j+1/2)))/2;
t2=(t(y(j-1/2))+t(y(j)))/2;
You cannot point arrays to a particular decimal index.As a workaround make sure that array Index is always a positive integer or a logical value.
Regards,
Gouri Chennuru
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