how to write matlab code for moments?
12 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
i have this code for calculating moments function [M]= moments(I) [r c]=size(I); m=zeros(r,c); % geometric moments for i=0:1 for j=0:1 for x=1:r for y=1:c m(i+1,j+1)=m(i+1,j+1)+(x^i*y^j*I(x,y)); end end end end
xb=m(2,1)/m(1,1); yb=m(1,2)/m(1,1);
% central moments u=[ 0 0 0 0;0 0 0 0;0 0 0 0;0 0 0 0]; for i=0:3 for j=0:3 for x=1:r for y=1:c u(i+1,j+1)=u(i+1,j+1)+(x-xb)^i*(y-yb)^j*I(x,y); end end end end
% scale invariant moments n=[ 0 0 0 0;0 0 0 0;0 0 0 0;0 0 0 0]; for i=0:3 for j=0:3 n(i+1,j+1)=u(i+1,j+1)/(u(1,1)^(1+(i+j)/2)); end end
%rotation invariant moments I_1= n(3,1)+ n(1,3); I_2=(n(3,1)- n(1,3) )^2+ (2*n(2,2))^2; I_3=(n(4,1)-3*n(2,3))^2+ (3*n(3,2)-n(1,4))^2; I_4=(n(4,1)+n(2,3))^2+ (n(3,2)+n(1,4))^2; I_5=(n(4,1)-3*n(2,3))*(n(4,1)+n(2,3))*((n(4,1)+n(2,3))^2-3*(n(3,2)+n(1,4))^2)+(3*n(3,2)-n(1,4))*(n(3,2)+n(1,4))*(3*(n(4,1)+n(2,3))^2-(n(3,2)+n(1,4))^2); I_6=(n(3,1)-n(1,3))*((n(4,1)+n(2,3))^2-(n(3,2)+n(1,4))^2)+ 4*n(2,2)*(n(4,1)+n(2,3))*(n(3,2)+n(1,4)); I_7=(3*n(3,2)-n(1,4))*(n(4,1)+n(2,3))*((n(4,1)+n(2,3))^2- 3*(n(3,2)+n(1,4))^2 )- (n(1,4)-3*n(2,3))*(n(3,2)+n(1,4))*(3*(n(4,1)+n(2,3))^2-(n(3,2)+n(1,4))^2);
M= [I_1 I_2 I_3 I_4 I_5 I_6 I_7];
but it gives same values for all images is this correct way to calculate moments?
0 Commenti
Risposta accettata
Iman Ansari
il 12 Apr 2013
Modificato: Iman Ansari
il 12 Apr 2013
You may need to convert your input image to double. In uint8 numbers greater than 255 became 255.
function [M]= moments(I)
I=double(I);
[r c]=size(I);
m=zeros(r,c);
% geometric moments
for i=0:1
for j=0:1
for x=1:r
for y=1:c
m(i+1,j+1)=m(i+1,j+1)+(x^i*y^j*I(x,y));
end
end
end
end
xb=m(2,1)/m(1,1);
yb=m(1,2)/m(1,1);
% central moments
u=[ 0 0 0 0;0 0 0 0;0 0 0 0;0 0 0 0];
for i=0:3
for j=0:3
for x=1:r
for y=1:c
u(i+1,j+1)=u(i+1,j+1)+(x-xb)^i*(y-yb)^j*I(x,y);
end
end
end
end
% scale invariant moments
n=[ 0 0 0 0;0 0 0 0;0 0 0 0;0 0 0 0];
for i=0:3
for j=0:3
n(i+1,j+1)=u(i+1,j+1)/(u(1,1)^(1+(i+j)/2));
end
end
%rotation invariant moments
I_1= n(3,1)+ n(1,3);
I_2=(n(3,1)- n(1,3) )^2+ (2*n(2,2))^2;
I_3=(n(4,1)-3*n(2,3))^2+ (3*n(3,2)-n(1,4))^2;
I_4=(n(4,1)+n(2,3))^2+ (n(3,2)+n(1,4))^2;
I_5=(n(4,1)-3*n(2,3))*(n(4,1)+n(2,3))*((n(4,1)+n(2,3))^2-3*(n(3,2)+n(1,4))^2)...
+(3*n(3,2)-n(1,4))*(n(3,2)+n(1,4))*(3*(n(4,1)+n(2,3))^2-(n(3,2)+n(1,4))^2);
I_6=(n(3,1)-n(1,3))*((n(4,1)+n(2,3))^2-(n(3,2)+n(1,4))^2)+ 4*n(2,2)*(n(4,1)...
+n(2,3))*(n(3,2)+n(1,4));
I_7=(3*n(3,2)-n(1,4))*(n(4,1)+n(2,3))*((n(4,1)+n(2,3))^2- 3*(n(3,2)+n(1,4))^2 )...
- (n(1,4)-3*n(2,3))*(n(3,2)+n(1,4))*(3*(n(4,1)+n(2,3))^2-(n(3,2)+n(1,4))^2);
M= [I_1 I_2 I_3 I_4 I_5 I_6 I_7];
5 Commenti
Akshit Vekariya
il 6 Mag 2015
Spostato: DGM
il 20 Feb 2023
will this code work on moment invariant...?
Sparsh Garg
il 15 Giu 2018
Spostato: DGM
il 20 Feb 2023
I am getting error Function definitions are not permitted in this context. please explain how to solve this error
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!