I did not understand the error which is called 'Error using symengine: Array sizes must match.' What should i do?

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x1=0.2232585;
x2=0.2232585;
iteration=0;
while true
iteration=iteration+1;
syms x1s x2s t
func=(x2s-x1s^2)^2+(1-x1s)^2;
dif_x1=diff(func,x1s);
dif_x2=diff(func,x2s);
grad_x1_temp=vpa(subs(dif_x1,x1));
grad_x1=vpa(subs(grad_x1_temp,x2));
grad_x2_temp=vpa(subs(dif_x2,x2));
grad_x2=vpa(subs(grad_x2_temp,x1));
tx1_temp=subs(dif_x1,x1-grad_x1*t);
tx1=subs(tx1_temp,x2s,x2-grad_x2*t);
tx2_temp=subs(dif_x2,x2s,x2-grad_x2*t);
tx2=subs(tx2_temp,x1s,x1-grad_x1*t);
eqn=tx1*grad_x1+tx2*grad_x2;
a=solve(eqn,t,'Real',true);
val_temp=vpa(subs(func,x1s,x1));
val=vpa(subs(val_temp,x2s,x2));
x1=x1-grad_x1*a;
x2=x2-grad_x2*a;
val_temp_end=vpa(subs(func,x1s,x1));
val_end=vpa(subs(val_temp_end,x2s,x2));
if(val_end>val)
break;
end
end
iteration
Error using symengine
Array sizes must match.
Error in sym/privBinaryOp (line 1013)
Csym = mupadmex(op,args{1}.s,
args{2}.s, varargin{:});
Error in - (line 7)
X = privBinaryOp(A, B,
'symobj::zipWithImplicitExpansion',
'_subtract');
Error in THE5 (line 26)
tx1_temp=subs(dif_x1,x1-grad_x1*t);
I keep getting these errors anyone has a clue?
  5 Commenti
Mert Picakci
Mert Picakci il 17 Gen 2021
Thank you, it seems your way of doing it is very efficient and less likely to get error. I’ll try defining the syms function and see wheter there is a problem or not.
Star Strider
Star Strider il 17 Gen 2021
My pleasure!
If I can understand what you are doing, I would write a specific solution (and post it as an Answer).

Accedi per commentare.

Risposta accettata

Deepak Meena
Deepak Meena il 21 Gen 2021
Hi Mert,
The Probelm arises in the 3rd iteration. In the 3rd Iteration x1 is size of 3x1 symfun and grad_x1 is size of 9x1 .
so the line
tx1_temp=subs(dif_x1,x1-grad_x1*t);
is throwing error as MATLAB is not able to resolve "x1- grad_x1*t".
So make sure both x1 and grad_x1 are of same size or "x1-grad_x1*t" should make sense like we can subtract 2x2 matrix from 1x2 like this :
syms x1 x2
p = [x1,x2;x2,x1];
t = [x1,x1] - p;
Thanks,
Deepak

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