How can I use symbolic variables while solving problems of MATLAB Cody?
3 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
syms x
x0 = 0.2;
f = cosh(x)/ (cosh(x0)-cosh(x))^0.5
I = int(f,0,x0);
I
Can someone verify this code snippet?
This code performs integration.
0 Commenti
Risposte (1)
John D'Errico
il 23 Gen 2021
Modificato: John D'Errico
il 23 Gen 2021
I recall that Cody disallows the use of essentially all toolboxes. Symbolic variables are only active for you, IF you have the symbolic toolbox.
Why are they disallowed? Because that would not be fair to others. Not everyone has every toolbox. In fact many people might not have any specific toolbox. So Cody, to be fair to all users, only should allow solutions that use base MATLAB because otherwise you might find a solution that uses some function that nobody else will have. And that could not possibly be fair to others to compare to code they cannot access.
I can probably find a statement to this effect, were I to go looking for one in the help, but then I just found this Answer:
What Steven says, I would absolutely trust to be fact. Given that - Steve, should I buy or sell XXX stock? ;-)
0 Commenti
Vedere anche
Categorie
Scopri di più su Symbolic Math Toolbox in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!