Locating point on x-axis where the slope is decreasing

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Dear all,
I used the following code to plot the angle over time:
figure
hold on
grid on
plot(Time, theta,'linewidth',1.5)
xlabel('Time [s]','FontWeight','bold')
ylabel('\theta [deg]','FontWeight','bold')
xlim([0 round(Time(end))])
legend('Opening angle','Location','northeast')
title('Opening angle')
The resulting graph is shown below. I want to index at what time the slope is decreasing. How can I do that?
The variables Time and theta to plot this graph can be found in the data.mat file.

Risposta accettata

Star Strider
Star Strider il 10 Mar 2021
A reasonably robust way is to use the ischange function:
D = load('data.mat');
Time = D.Time;
theta = D.theta;
[TF,m,b] = ischange(theta, 'linear', 'Threshold',5);
chgpts = [find(TF); m(TF); b(TF)].';
chgidx = find(chgpts(:,2)<0,1);
figure
plot(Time, theta,'linewidth',1.5)
hold on
plot(Time(chgpts(chgidx(:,1))), theta(chgpts(chgidx(:,1))), 'xr')
hold off
grid on
xlabel('Time [s]','FontWeight','bold')
ylabel('\theta [deg]','FontWeight','bold')
xlim([0 round(Time(end))])
legend('Opening angle','Location','northeast')
title('Opening angle')
producing:
The ‘Time’ value is then:
ChangePointTime = Time(chgpts(chgidx(:,1)));
that here is 6.01 seconds.
  4 Commenti
Tessa Kol
Tessa Kol il 10 Mar 2021
Thank you so much for the code and explanation!

Accedi per commentare.

Più risposte (1)

Sargondjani
Sargondjani il 10 Mar 2021
Bascially you want to get the index when the change in theta becomes negative:
dtheta = diff(theta);
index = find(dtheta<0,1);%the 1 refers to the first entry where the statement is true

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