# Find function - scalar result?

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Cyril CRIER il 8 Apr 2021
Commentato: Jan il 5 Mar 2022
Hello,
I'm trying to get the row number where my "goal" value (hier max time /10) is inside my tolerance of 0.001.
%Speed_profil.motorized.time -> Vector 100x1 from 0 to 4,5sec
Ramp=10;
goal = (Speed_profil.motorized.time(end,1)/Ramp);
idx_tol_mot = find(abs(Speed_profil.motorized.time-goal) < 0.001);
The fact to use the find funciton gives me a Vactor as a result.
I'm using this idx_tol_mot in an equation of the form y=ax+b to limit my Speed_profil.motorized.time vector (100x1 matrix).
Speed_profil.motorized.closing.values(1:idx_tol_mot,1) = (- a_mot * Speed_profil.motorized.time(1:idx_tol_mot,1));
Is there an alternative to the find function which can give a scalar variable? or can I convert the idx_tol_mot variable?
Thanks
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### Risposte (1)

Jan il 8 Apr 2021
Modificato: Jan il 8 Apr 2021
Maybe:
idx_tol_mot = find(abs(Speed_profil.motorized.time-goal) < 0.001, 1, 'first');
or
idx_tol_mot = find(abs(Speed_profil.motorized.time-goal) < 0.001, 1, 'last');
But this the output can be empty also, if no matching values are found.
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Alexander Lachenmaier il 5 Mar 2022
Hi,
have you found a solution to this error? I am facing the exact same problem at the Moment.
Alex
Jan il 5 Mar 2022
@Alexander Lachenmaier: The original question wasn't clear. The OP showed a method, which replies a vector and asked, how to get a scalar. But when all we see is the code to produce a vector, it is impossible to guess, what it wanted instead.
Therefore I'm astonished, that you have "the same problem". Prefer to open a new thread and explain the details of your code.

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