title according to the file name

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Does anybody know how to (in a plot) put the ‘title’ as the name of the file where the X,Y,Z variables are included? the idea is to generate several and independent plots, based on ‘imagesc’, ‘contolchart’ and other plotting functions. Thanks.
  4 Comments
Rik
Rik on 24 Mar 2022
The fileparts function should do what you need:
[p,f,e]=fileparts('C:\path\morepath\filename.csv')
p = 0×0 empty char array
f = 'C:\path\morepath\filename'
e = '.csv'
%(these results are on Linux, on Windows you should get this)
p = 'C:\path\morepath'
f = 'filename'
e = '.csv'

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Accepted Answer

Constantino Carlos Reyes-Aldasoro
Perhaps you want to add values to the titles of your figures, try something like this
for k=1:9
subplot(3,3,k)
title(strcat('Subplot number =',num2str(k)))
end
If this does not answer your question, we would need more information.
  1 Comment
Adam Danz
Adam Danz on 15 Apr 2021
or,
title(['Subplot number = ', num2str(k)])
or,
title(sprintf('Subplot number = %d', k))

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More Answers (1)

Chunru
Chunru on 15 Apr 2021
filename = "abc";
load(filename, "x", "y");
plot(x, y)
title(sprintf("File name: %s", filename));
  1 Comment
Rik
Rik on 15 Apr 2021
You shouldn't encourage loading variables like this. Always load to a struct:
S=load(filename, "x", "y");x=S.x;y=S.y;

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