How to find and print elements of a character array?

Hello everyone,

This is the first time im dealing with words in matlab

I need help to print a character string

eg

mem=['ISNT-60','ISA55-55-6 b/b','ISMC-100 b/b','ISMC-125 b/b','ISMB-225','ISMC-175 b/b','ISHB-250','ISMB-400'];

d=[1,5,8,5,4,2,4];

I want to matllab to print character strings in char array matrix (mem) based on elemts in matrix d

i.e mem(d(i)) for i=1 to 7

so say mem(d(1))= ISNT-60

function opt=dcde(A1,mem)
        c=dec2bin(A1(1),21);
        i=1;
        count=1;
while count<20
        d=c(count:count+2);
        d=bin2dec(d)
        opt=(mem(d));
        fprintf('member id %d, :%f \n',i,opt);
        count=count+3;
        i=i+1;
end
end

This code takes a number as inputs converts it into 21 igit binary splits it into 3 digit data points (represeted by matrix d)

based on the value of 3 digit code i want to print name of the section given in matrix mem

This code is printing a number rather than a character string and i dont understand why

Answer 1

[David Hill]

Use a cell array instead.

mem={'ISNT-60','ISA55-55-6 b/b','ISMC-100 b/b','ISMC-125 b/b','ISMB-225','ISMC-175 b/b','ISHB-250','ISMB-400'};
mem{3}

[Amith Mallya]

Thank you, it works

Answer 2

[DGM]

Is there some reason that you need to keep all the strings concatenated into one long character vector? Why not store them in a cell array? Also, you'll need to handle cases where there are '000' runs in c, otherwise you'll wind up with errors. As to why you were getting numbers out, you're trying to display a character string as a floating point number (%f).

mem={'ISNT-60','ISA55-55-6 b/b','ISMC-100 b/b','ISMC-125 b/b','ISMB-225','ISMC-175 b/b','ISHB-250','ISMB-400'};

A1=299666 % this particular number converts to a binary string without any zero triplets

c=dec2bin(A1(1),21);
i=1;
count=1;
while count<20
    d=c(count:count+2);
    d=bin2dec(d)
    if d==0
        % do something different, because zero isn't a valid index
    else
        opt=(mem{d});
        fprintf('member id %d, :%s \n',i,opt);
    end
    count=count+3;
    i=i+1;
end

[Amith Mallya]

No reason to take character array, this is the 1st time i am using character strings, so was confused,

Thank you for pointing out the problem with 000 , i deal with it by adding 1 to d (as i have 8 options for mem), i missed it in this code,

Thanks for your quick reply