find a row number in text file for certain condition

data=[1.2;1.0;0.05;0.4;0.3;0.2;0.1;0.05;0.04;0.03;0.03;0.02;0.01;0.001;0.01;0.01;0.001 ] ;

Here, the answer to my problem is 8th row, because the 10 consecutive rows from the 8th row are smaller than 0.10. How can I write a code to determine the row number which satisfies this condition?

[Jan]

Why do you menation a text file?

[sermet OGUTCU]

The text file includes the numeric data as n (row) x 1 (column)

Answer 1

[Jan]

data = [1.2;1.0;0.05;0.4;0.3;0.2;0.1;0.05;0.04;0.03;0.03;0.02;0.01;0.001;0.01;0.01;0.001 ] ;
[b, n, index] = RunLength(data < 0.1);
match = find(b & n >= 10, 1);
result = index(match)

result = 8

function [b, n, index] = RunLength(x)
d = [true; diff(x(:)) ~= 0];  % TRUE if values change
b = x(d);                     % Elements without repetitions
k = find([d.', true]);        % Indices of changes
n = diff(k);                  % Number of repetitions
index = k(1:numel(k) - 1);
if iscolumn(x)
    n     = n.';
    index = index.';
end
end

[Jan]

[MOVED from flags] sermet OGUTCU wrote: This solution is highly effective.

@sermet OGUTCU: We use flags here to inform the editors about inappropriate contents like rudeness.