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I need to plot the sum of 2 sine curves. I can successfully plot (x,y1) and plot(x,y2), they are smooth curves, however when i try to plot(x,y) where y = y1+y2 the curve comes out like this? how do i fix this i dont know what i am doing wrong? Thanks

3 Commenti

Stephen23
Stephen23 il 11 Mag 2021
Modificato: Stephen23 il 11 Mag 2021
"...however when i try to plot... the curve comes out like this"
You are plotting lots of zeros (to within floating point precision), because that is exactly what you calculated.
"how do i fix this i dont know what i am doing wrong?"
You need to consider the B factor. Note that for a B which is an integer multiple of 2*pi (and you defined B as 4*pi, which is clearly a multiple of 2*pi), the following identity holds true:
sin(B*X) = -sin(B*(1-X))
For example:
B = 2*pi;
X = rand(1,9);
sin(B*X)
ans = 1×9
-0.6044 -0.8824 -0.4910 -0.9397 -0.7891 0.9338 0.8413 0.9918 -0.9736
sin(B*(1-X))
ans = 1×9
0.6044 0.8824 0.4910 0.9397 0.7891 -0.9338 -0.8413 -0.9918 0.9736
That is why you are plotting zeros (or at least values very very very close to zero).
Stephen23
Stephen23 il 16 Mag 2021
Modificato: Stephen23 il 16 Mag 2021
Original question by Tyler Daines retrieved from Google Cache (unfortunately their deleted comments are not included):
Trying to plot a sine+sine function but not getting a smooth curve
I need to plot the sum of 2 sine curves. I can successfully plot (x,y1) and plot(x,y2), they are smooth curves, however when i try to plot(x,y) where y = y1+y2 the curve comes out like this? how do i fix this i dont know what i am doing wrong? Thanks
Rena Berman
Rena Berman il 29 Giu 2021

(Answers Dev) Restored edit

Accedi per commentare.

Risposte (2)

DGM
DGM il 11 Mag 2021
What you're looking at isn't meaningful. It's all just rounding error. You're essentially doing this:
y = sin(x) - sin(x);
I'm guessing there's some phase component that's not defined right yet, but I can't really guess at what you need it to be.
f = 2;
A = 1;
v = 1;
L = 1;
l = v/f;
B = (2*pi)/l;
w = 2*pi*f;
t = 0;
x = 0:0.0001:L;
z1 = A*sin(B*x - w*t);
z2 = A*sin(B*(L-x) - w*t);
y = z1+z2;
plot(x,z2); hold on
plot(x,z1);
For the future, please just paste your code using the code formatting tools. I had to retype all that and deal with the sub-pixel ambiguity differentiating the character '1' and 'l'.

2 Commenti

Tyler Daines
Tyler Daines il 11 Mag 2021
Sorry mate i havent used this forum before will do in the future.
DGM
DGM il 11 Mag 2021
No worries. It was short enough.

Accedi per commentare.

RAHUL MAURYA
RAHUL MAURYA il 12 Mag 2021

0 voti

clear all;
clc;
f = 2;
A = 1;
v = 1;
L = 1*(180/(pi));
l = v/f;
B = ((2*pi)/l)*(180/pi);
w = 2*pi*f;
t = 0;
x=0:0.0001:L;
z1 = (A*sind(B*x - w*t));
z2 = A*sind(B*(L-x) - w*t);
y=(z1+z2);
subplot(3,1,1);
plot(x,z1)
title('X,Z1')
axis([0 10 -1 1])
subplot(3,1,2);
plot(x,z2)
title('X,Z2')
axis([0 10 -1 1])
subplot(3,1,3);
plot(x,y)
title('X,Z1+Z2')
axis([0 10 -2 2])
Convert B and L in radian to degree.

Richiesto:

il 11 Mag 2021

Modificato:

il 29 Giu 2021

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