How to shorten the amount of decimals?

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Garrett
Garrett il 20 Mag 2021
Commentato: Steven Lord il 20 Mag 2021
I keep getting really long numerical values as output:
An =
0.024234995896557227359496464702679*alpha
0.15943782393832228295849338860996*alpha
-0.12536421301907562828842055676579*alpha
-0.03553313448766475646513348990721*alpha
-0.13243736773001789371670675334921*alpha
-1.1264101534225156844164497805098*alpha
0.032972016135334102699585911872833*alpha
0.10090249826183501633095025194958*alpha
0.094800519200094255394106279895626*alpha
-0.031355837620080097288391753550103*alpha
How can i reduce this to only a couple decimal places?
Entire code for reference:
clc
clear
N = 19;
AR = 6;
n =1:2:N;
b = 6;
Vinf = 1;
c = 1;
deltay = b./(N+1);
y0n = -(b./2)+n.*deltay;
syms alpha
A = sym('A', [1, N]);
A = A(1:2:end);
Pi = sym(pi);
theta = (linspace((Pi/6),(Pi/2),numel(n)).');
S1 = sum(A.*sin(n.*(theta)));
S2 = sum(n.*A.*(sin(n.*(theta))./sin((theta))));
eq1 = (2*AR/pi)*S1+S2 == alpha;
[A,b] = equationsToMatrix(eq1, A);
x = linsolve (A,b);
An = vpa(x)

Risposta accettata

Star Strider
Star Strider il 20 Mag 2021
Use the digits function.
  1 Commento
Steven Lord
Steven Lord il 20 Mag 2021
You can instead call vpa with two inputs if you don't want to affect the number of digits for future calls.

Accedi per commentare.

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