finding only unique values

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Bernard
Bernard il 22 Ago 2013
Suppose you have a column vector, the values are integers(in order) but some of them are repeated, e.g. it could be [1,1,1,1,2,3,3,4,5,5,5,5,5] I want to find the indices of unique values e.g. the index of 2 and 4 in the aforementioned example. the unique function in matlab returns on top of truly unique the first value of any nonunique value, so it would return the index of the first 1, the first 3 and first 5 but I don't want those

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the cyclist
the cyclist il 22 Ago 2013
Modificato: the cyclist il 22 Ago 2013
Maybe call these the "singleton" values. Here's one way:
x = [1,1,1,1,2,3,3,4,5,5,5,5,5];
unique_x = unique(x);
count_x = hist(x,unique_x);
singleton_x = unique_x(count_x==1)
  1 Commento
Bernard
Bernard il 22 Ago 2013
brilliant this saved me time thanks

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Più risposte (2)

David Sanchez
David Sanchez il 22 Ago 2013
a=[1,1,1,1,2,3,3,4,5,5,5,5,5];
x = unique(a)
y = histc(a,x)==1;
lonely_values = find ( y == 1 )
or:
lonely_values = find ( (histc(a,unique(a))==1) == 1 )
lonely_values =
2 4

Azzi Abdelmalek
Azzi Abdelmalek il 22 Ago 2013
[ii,jj]=sort(x);
out=sort(jj(strfind(logical([1 diff(ii) 1]),[true,true])))

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