How to create concentric circles?

Hello, I want to generate a series of concentric circles by filling each ring with a different color. The result I want to obtain is similar to the figure. With the code I present, I get the figure 2. How could I assign a color to each ring between the circles?
Thanks in advance
clear;
clc;
close all
x_center = 0;
y_center = 0;
pellet = 0.3355;
gap = 0.350;
w14re = 0.354;
re = 0.355;
clad = 0.455;
sicfib = 0.458;
radius_array = [pellet gap w14re re clad sicfib];
for i = 1:5
radius = 5;
theta = 0:pi/50:2*pi;
x_circle_1 = radius_array(i) * cos(theta) + x_center;
y_circle_1 = radius_array(i) * sin(theta) + y_center;
x_circle_2 = radius_array(i+1) * cos(theta) + x_center;
y_circle_2 = radius_array(i+1) * sin(theta) + y_center;
fig1 = plot(x_circle_1, y_circle_1, 'k-', 'LineWidth', 0.5);
hold on
fig2 = plot(x_circle_2, y_circle_2, 'k-', 'LineWidth', 0.5);
hold on
axis equal
axis off
end

 Risposta accettata

x_center = 0;
y_center = 0;
pellet = 0.3355;
gap = 0.350;
w14re = 0.354;
re = 0.355;
clad = 0.455;
sicfib = 0.458;
radius_array = [pellet gap w14re re clad sicfib]
radius_array = 1×6
0.3355 0.3500 0.3540 0.3550 0.4550 0.4580
cm = turbo(numel(radius_array)); % Choose The Appropriate 'colormap'
for i = 1:5
radius = 5;
theta = 0:pi/50:2*pi;
x_circle_1 = radius_array(i) * cos(theta) + x_center;
y_circle_1 = radius_array(i) * sin(theta) + y_center;
x_circle_2 = radius_array(i+1) * cos(theta) + x_center;
y_circle_2 = radius_array(i+1) * sin(theta) + y_center;
fig1 = plot(x_circle_1, y_circle_1, 'k-', 'LineWidth', 0.5);
hold on
fig2 = plot(x_circle_2, y_circle_2, 'k-', 'LineWidth', 0.5);
patch([x_circle_1, fliplr(x_circle_2)], [y_circle_1, fliplr(y_circle_2)],cm(i,:), 'EdgeColor',cm(i,:))
hold on
axis equal
axis off
end
Note —
In the patch call, the EdgeColor is the color of the patch it encloses. To eliminate the edge colours instead, specify 'none' instead of cm(i,:).
.

2 Commenti

Yro
Yro il 15 Giu 2021
Great, it works. Thank you very much for your help.
As always, my pleasure!

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R2018a

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